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# Selina Concise Mathematics - Part II Solution for Class 10 Mathematics Chapter 5 - Quadratic Equations

## Selina Textbook Solutions Chapter 5 - Quadratic Equations

Selina Textbook Solutions are a perfect way to ace your examination with high marks. These Textbook Solutions are extremely helpful for solving difficult questions in the ICSE Class 10 Mathematics exam. Our Selina Textbook Solutions are written by our subject experts. Find all the answers to the Selina textbook questions of Chapter 5 - Quadratic Equations.

All Selina textbook questions of Chapter 5 - Quadratic Equations solutions are created in accordance with the latest ICSE syllabus. These free Textbook Solutions for ICSE Class 10 Selina Concise Mathematics will give you a deeper insight on the fundamentals in this chapter and will help you to score more marks in the final examination. ICSE Class 10 students can refer to these solutions while doing their homework and while studying and revising for the Mathematics exam.

Exercise/Page

## Selina Concise Mathematics - Part II Solution for Class 10 Mathematics Chapter 5 - Quadratic Equations Page/Excercise 5(A)

Solution 1

Solution 2(ii)

x2 + (p - 3)x + p = 0

Here, a = 1, b = (p - 3), c = p

Since, the roots are equal,

b2- 4ac = 0

(p - 3)2- 4(1)(p) = 0

p2 + 9 - 6p - 4p = 0

p2- 10p + 9 = 0

p2-9p - p + 9 = 0

p(p - 9) - 1(p - 9) = 0

(p -9)(p - 1) = 0

p - 9 = 0 or p - 1 = 0

p = 9 or p = 1

Solution 2(i)

Solution 3

Solution 4

Solution 5

## Selina Concise Mathematics - Part II Solution for Class 10 Mathematics Chapter 5 - Quadratic Equations Page/Excercise 5(B)

Solution 1

Solution 2

Solution 3

Solution 4

Solution 5

Solution 6

Solution 7

Solution 8

Solution 9

Solution 10

Solution 11

Solution 12

Solution 13

Solution 14

Solution 15

Solution 16

Solution 17

Solution 18

Solution 19

Solution 20

Solution 21

Solution 22(ii)

Solution 22(i)

Solution 23

If a+1=0, then a = -1

Put this value in the given equation x2 + ax - 6 =0

Solution 24

If a + 7 =0, then a = -7

and b + 10 =0, then b = - 10

Put these values of a and b in the given equation

Solution 25

4(2x+3)2 - (2x+3) - 14 =0

Put 2x+3 = y

Solution 26

Consider the equation, 6x2 - x - 2=0

Put  in L.H.S.

Since L.H.S.= R.H.S., then is a solution of the given equation.

Solution 27

x2 - 3x +2=0

Put x = -1 in L.H.S.

L.H.S. = (-1)2 - 3(-1) +2

= 1 +3 +2=6 R.H.S.

Then x = -1 is not the solution of the given equation.

Solution 28

7x2+mx - 3=0

Given x = is the solution of the given equation.

Put given value of x in the given equation

Solution 29

Solution 30

Solution 31

Solution 32

or x = -(a + b)

Solution 33

Solution 34

## Selina Concise Mathematics - Part II Solution for Class 10 Mathematics Chapter 5 - Quadratic Equations Page/Excercise 5(C)

Solution 1

Solution 2

Solution 3(i)

Solution 3(ii)

Solution 3(iii)

Solution 3(iv)

Solution 4

Solution 5

Solution 6

Solution 7

Solution 8

Solution 9

Consider the given equation:

Solution 10

Solution 11

x2 - 3(x + 3) = 0

## Selina Concise Mathematics - Part II Solution for Class 10 Mathematics Chapter 5 - Quadratic Equations Page/Excercise 5(D)

Solution 1

Solution 2

Solution 3

Solution 4

Solution 5

Solution 6

Solution 7

Solution 8

Solution 9

Solution 10

Solution 11

Solution 12

Solution 13

Solution 14

Solution 15

Solution 16

Solution 17

Solution 18

Solution 19

Solution 20

Consider the given equation:

## Browse Study Material

TopperLearning provides step-by-step solutions for each question in each chapter. Access Chapter 5 - Quadratic Equations  for ICSE Class 10 Mathematics free of cost. The solutions are provided by our subject matter experts. Refer to our solutions for the Selina Concise Mathematics textbook to revise the whole chapter and clear your fundamentals before the examination. By referring to the solutions for this chapter and the others, we hope that you are able to write your exams well.

# Text Book Solutions

ICSE X - Mathematics

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