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# Selina Concise Mathematics - Part II Solution for Class 10 Mathematics Chapter 17 - Circles

## Selina Textbook Solutions Chapter 17 - Circles

Selina Textbook Solutions are a perfect way to ace your examination with high marks. These Textbook Solutions are extremely helpful for solving difficult questions in the ICSE Class 10 Mathematics exam. Our Selina Textbook Solutions are written by our subject experts. Find all the answers to the Selina textbook questions of Chapter 17 - Circles.

All Selina textbook questions of Chapter 17 - Circles solutions are created in accordance with the latest ICSE syllabus. These free Textbook Solutions for ICSE Class 10 Selina Concise Mathematics will give you a deeper insight on the fundamentals in this chapter and will help you to score more marks in the final examination. ICSE Class 10 students can refer to these solutions while doing their homework and while studying and revising for the Mathematics exam.

Exercise/Page

## Selina Concise Mathematics - Part II Solution for Class 10 Mathematics Chapter 17 - Circles Page/Excercise 17(A)

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(i) AEB =

(Angle in a semicircle is a right angle)

Therefore EBA = - EAB = - =

(ii) AB ED

Therefore DEB = EBA =                        (Alternate angles)

Therefore BCDE is a cyclic quadrilateral

Therefore DEB  BCD =

[Pair of opposite angles in a cyclic quadrilateral are supplementary]

Therefore BCD =  - =

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1. ABCD is a cyclic quadrilateral

mDAB = 180° - DCB

= 180° - 130°

= 50°

mDAB + mADB + mDBA = 180°

50° + 90° + mDBA = 180°

mDBA = 40°

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