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Concise Chemistry Part II - Selina Solution for Class 10 Chemistry Chapter 13 - Practical Work

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Selina Textbook Solutions Chapter 13 - Practical Work

Selina Textbook Solutions are a perfect way to ace your examination with high marks. These Textbook Solutions are extremely helpful for solving difficult questions in the ICSE Class 10 Chemistry exam. Our Selina Textbook Solutions are written by our subject experts. Find all the answers to the Selina textbook questions of Chapter 13 - Practical Work.

All Selina textbook questions of Chapter 13 - Practical Work solutions are created in accordance with the latest ICSE syllabus. These free Textbook Solutions for ICSE Class 10 Selina Concise Chemistry will give you a deeper insight on the fundamentals in this chapter and will help you to score more marks in the final examination. ICSE Class 10 students can refer to these solutions while doing their homework and while studying and revising for the Chemistry exam.

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Concise Chemistry Part II - Selina Solution for Class 10 Chemistry Chapter 13 - Practical Work Page/Excercise 13

Solution 1

(a) (i) Chemical test for ammonia:

If a rod dipped in concentrated hydrochloric acid is brought near ammonia gas, dense white fumes of ammonium chloride (NH4Cl) are formed.

(ii) Chemical test for Sulphur dioxide:

It decolorizes pink coloured potassium permanganate solution.

(iii) Chemical test for HCl:

When HCl gas is passed through AgNO3 solution, white precipitates of AgCl are formed which gets dissolved in excess of NH4OH.

(iv) Chemical test for Chlorine:

It turns moist starch iodide paper (KI + starch solution) blue black.

(v) Chemical test for Carbon dioxide:

When this gas is passed through lime water, it turns milky due to the formation of white precipitates of CaCO3 and on passing excess of carbon dioxide gas, this milkiness disappears.

(vi) Chemical test for oxygen:

This gas is absorbed in colourless alkaline solution of pyrogallol and turns it dark brown.

(vii)Chemical test for hydrogen:

It burns with a pop sound when a burning taper is brought near it.

(b) Ammonia is a basic gas and its basic nature is suspected through litmus paper test because it changes the colour of red litmus paper to blue.

(c) Chlorine, carbon dioxide, hydrogen chloride, hydrogen sulphide and sulphur dioxide are acidic gases since they convert blue litmus to red.

(d) A is chlorine and B is Sulphur dioxide.

(e) Water vapour.

Solution 2

(a)O2

(b)NH3

(c)Water vapour

(d)SO2

Solution 3

(a) Na2CO3 and K2CO3

(b) SO2

(c) CO2

(d) Cl2

(e) H2S

Solution 4

Silver nitrate and ammonium nitrate.

Solution 5

(a) Cl-

(b) SO42-

(c) CO32-

(d) SO32-

Solution 6

(a) Since the salt solution turned blue litmus red hence the salt may be an acid.

(b) Since addition of barium chloride into the solution of salt gave white precipitate so the salt may contain SO42-, SO32-, CO32- anion.

(c) The flame test of the salt gives persistent golden yellow colourisation which suggests presence of Na+ ion.

Solution 7

                  

          (a) Ca2+

          (b) Cu

          (c) The three ways are:

          i. Ammonia gas turns moist red litmus blue.

          ii. If a rod dipped in concentrated HCl is brought near the gas, dense white fumes of NH4Cl are formed.

          iii. The gas turns colourless Nessler's reagent i.e. K2HgI4 brown.

Solution 8

Hydrogen sulphide

Ammonia

Sulphur dioxide

Hydrogen chloride

Shake the gas with red litmus solution

No change in the colour of litmus solution

Red litmus solution becomes blue in colour.

No change in the colour of litmus solution

No change in the colour of litmus solution

Shake the gas with blue litmus solution

Blue litmus solution becomes red in colour.

No change in the colour of blue litmus solution.

Blue litmus solution becomes red in colour.

Blue litmus solution becomes red in colour

Apply a burning splint to a gas

No reaction.

No reaction.

No reaction.

No reaction.

Solution 9

(P) Ammonium chloride

(Q) Calcium

(R) Calcium hydroxide

(S) Lead (II) Nitrate

(T) Calcium Oxide

(U) Lead (II) Oxide

(V) Chlorine

(W) Hydrogen chloride

Solution 10

Carbonate

Colour of residue on cooling

Zinc Carbonate

white

Lead Carbonate

yellow

Copper Carbonate

black

Solution 11

(i)Sodium carbonate and sodium sulphite can be distinguished by using acidified K2Cr2O7:

Take a small quantity of salt in a test tube; add dil. H2SO4.and warm if necessary. Now if on bringing a filter paper moistened with acidified K2Cr2O7 near the gas evolved, the orange colour of the paper turns green then it is sodium sulphite.

(ii)Sodium thiosulphate and sodium sulphite:

The salts can be distinguished by using silver acetate. To the salt silver acetate and dil. HNO3 are added. If there is formation of a white precipitate which slowly turns black then it is thiosulphate anion since silver acetate forms Ag2S2O3 which being unstable in acid solution gets converted to black Ag2S.

(iii)Sodium hydroxide solution and ammonium hydroxide solution:

These salts can be distinguished by using a metal cation like calcium. When we add calcium salt to sodium hydroxide and ammonium hydroxide, then a white curdy ppt. is formed only in case of sodium hydroxide.

(iv)Ammonium sulphate and sodium sulphate:

These salts can be distinguished by using KOH. When KOH is added to ammonium sulphate, ammonia gas is evolved. Whereas there is no evolution of ammonia gas in case of sodium sulphate.

(v)Add barium chloride solution to sulphuric acid, nitric acid and hydrochloric acid. A white precipitate is formed in dilute sulphuric acid, and no such precipitate is formed in nitric acid and hydrochloric acid.

BaCl2(aq)  + H2SO4(aq) → BaSO4(s) + 2HCl(aq)

Solution 12

Aqueous salt solution

Colour of the precipitate when NaOH is added in small quantity

Nature of the(soluble or insoluble) when NaOH is added in excess

copper (II) sulphate

zinc nitrate

 

lead nitrate

calcium chloride

iron (III) sulphate

(i)Pale blue

 

(ii) White gelatinous

(iii)White chalky

(iv)White curdy

(v) Reddish brown

 

(vi)Insoluble

 

(viii)Soluble

 

(viii)Soluble

(ix)Insoluble

(x)Insoluble

Solution 13

(a)Lead chloride as precipitate and sodium nitrite are formed.

(b)

 

Zinc chloride

Zinc nitrate

Zinc sulphate

Barium chloride

No reaction

No reaction

White ppt. is obtained

Lead nitrate

No reaction

No reaction

No reaction

(c)Dilute sulphuric acid liberates carbon dioxide from metallic carbonates and bicarbonates. Carbon dioxide when bubbled into a test tube containing calcium hydroxide solution turns it milky.

Solution 14

(I)Iron (II) Sulphate and Magnesium sulphate

(II)Iron (III) chloride and Zinc Chloride

(III)Lead nitrate

(IV)Copper nitrate.

(V)Lead nitrate.

Solution 15

 

Solution

Acids

Alkalies

(a) Alkaline phenolphthalein solution

(b) Methyl orange solution

(c) Neutral litmus solution

Colourless

Pink

Red

Pink

Yellow

Blue

 

Solution 16

Salt

Anion

A

Cl-

B

S2-

C

NO3-

D

SO32-

E

CO32-

Solution 2008

(a) (ii) Iron[II] sulphate

(b) (i) Gas A is ammonia gas.

     (ii) Acid B is nitric acid.

     (iii) Gas C is hydrogen sulphide.

     (iv) Gas D is sulphur dioxide.

     (v) Liquid E is ethanol.

Solution 2009

(a) (iii) Acidified potassium dichromate paper

 

(b) R is ferrous sulphate.

 

(c)

i. When BaCl2 solution is added to the given solution, ZnSO4 gives a white ppt. of barium sulphate, while no ppt. is obtained with ZnCl2 solution.

 

ii. When NaOH solution is added to the given solution, iron (II) chloride gives a dirty green ppt. of ferrous hydroxide, while reddish brown ppt. of iron(III) hydroxide is obtained with iron (III) chloride.

 

iii. When AgNO3 solution is added to the given solution, CaCl2 solution gives a white ppt., while no change is observed with calcium nitrate solution.

Solution 2010

(a)

(i) C. Chromium sulphate

(ii) A. Nitroso iron (II) sulphate

(b) (i) Litmus turns blue to red, and then gets bleached.

     (ii) Paper turns from pink to white.

(c) MgSO4 + BaCl2 MgCl2 + BaSO4

Solution 2011

(a) Barium chloride

Solution 2012

(a) Sulphur dioxide

(b) (i) Nitrate ion, NO3-

     (ii) Chloride ion, Cl-

      (iii) Carbonate ion, CO32-

     (iv) Sulphate ion, SO42-

(c)

i. On adding dil. sulphuric acid to sodium carbonate, a colourless and odourless gas is evolved which has no action on acidified potassium dichromate paper.

Na2CO3+ H2SO4→ Na2SO4+ H2O + CO2

Sodium sulphite on adding dil. sulphuric acid liberates a colourless gas having burning sulphur smell and turns acidified potassium dichromate paper from orange to green.

Na2SO3 + H2SO4 Na2SO4 + H2O + SO2

K2Cr2O7 + 3SO2 + H2SO4 → K2SO4 + Cr2(SO4)3 + H2O

(Orange)                                   (Green)

ii. Ferrous nitrate on reaction with little NaOH produces a dirty green precipitate which is insoluble in excess. Lead nitrate on reaction with little NaOH produces white precipitate which is soluble in excess.

iii. Add a little dil. sulphuric acid to copper oxide and manganese dioxide and heat gently. The copper oxide reacts to produce a blue solution of copper sulphate. The manganese dioxide gives a colourless solution.

CuO + H2SO4→ CuSO4 + H2O

                        (Blue)

MnO2 + 2H2SO4→MnSO4 + 2H2O

                             (Colourless)

 

(d) The blue colour of copper sulphate solution discharge and a reddish brown layer of copper are seen.

(e) AgNO3 + NaCl → AgCl + NaNO3

Solution 2013

(a)

i. Add silver nitrate solution to both solutions. Sodium chloride will form a curdy white ppt., whereas sodium nitrate will not undergo any reaction.

ii. Hydrogen chloride gas gives thick white fumes of ammonium chloride when a glass rod dipped in ammonia solution is held near the vapour of the acid, whereas no white fumes are observed in case of hydrogen sulphide gas.

iii. Calcium nitrate forms no ppt. even with addition of excess of NH4OH, whereas zinc nitrate forms a white gelatinous ppt. which dissolves in excess of NH4OH.

iv. Carbon dioxide gas has no effect on acidified KMnO4 or K2Cr2O7, but sulphur dioxide turns potassium permanganate from pink to colourless.

(b) (i) Carbon monoxide

Solution 2014

(a) Sodium nitrate on treatment with dilute sulphuric acid gives sodium bisulphate and nitric acid.

     NaNO3 + H2SO4 →NaHSO4 + HNO3

Sodium sulphite on treatment with dilute sulphuric acid gives sodium sulphate and sulphur dioxide.

     Na2SO3 + H2SO4 → Na2SO4 + H2O + SO2

(b) When moist starch iodide paper is introduced into chlorine gas, chlorine oxidises iodide to iodine, which shows up as blue when complexed with starch.

(c) On carrying out the flame test with a salt P, a brick red flame is obtained. Hence, the cation P is Ca2+.

(d) Gas Q turns moist lead acetate paper silvery black. Hence, the gas is H2S.

(e) pH of liquid R is 10. Hence, substance R is a base.

TopperLearning provides step-by-step solutions for each question in each chapter. Access Chapter 13 - Practical Work  for ICSE Class 10 Chemistry free of cost. The solutions are provided by our subject matter experts. Refer to our solutions for the Selina Concise Chemistry textbook to revise the whole chapter and clear your fundamentals before the examination. By referring to the solutions for this chapter and the others, we hope that you are able to write your exams well. 

Text Book Solutions

ICSE X - Chemistry

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