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Concise Chemistry Part II - Selina Solution for Class 10 Chemistry Chapter 2 - Chemical Bonding

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Selina Textbook Solutions Chapter 2 - Chemical Bonding

Selina Textbook Solutions are a perfect way to ace your examination with high marks. These Textbook Solutions are extremely helpful for solving difficult questions in the ICSE Class 10 Chemistry exam. Our Selina Textbook Solutions are written by our subject experts. Find all the answers to the Selina textbook questions of Chapter 2 - Chemical Bonding.

All Selina textbook questions of Chapter 2 - Chemical Bonding solutions are created in accordance with the latest ICSE syllabus. These free Textbook Solutions for ICSE Class 10 Selina Concise Chemistry will give you a deeper insight on the fundamentals in this chapter and will help you to score more marks in the final examination. ICSE Class 10 students can refer to these solutions while doing their homework and while studying and revising for the Chemistry exam.

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Concise Chemistry Part II - Selina Solution for Class 10 Chemistry Chapter 2 - Chemical Bonding Page/Excercise Intext 1

Solution 1

Atoms lose, gain or share electrons to attain noble gas configuration.

Solution 2

(a) A chemical bond may be defined as the force of attraction between any two atoms, in a molecule, to maintain stability.

(b) The chemical bond formed between two atoms by transfer of one or more electrons from the atom of a metallic electropositive element to an atom of a non-metallic electronegative element is called as electrovalent bond.

(c) The chemical bond formed due to mutual sharing of electrons between the given pairs of atoms of non-metallic elements is called as a covalent bond.

Solution 3

Conditions for formation of Ionic bond are:

(i) The atom which changes into cation should possess 1, 2 or 3 valency electrons. The other atom which changes into anion should possess 5, 6 or 7 electrons in the valence shell.

(ii) A high difference of electronegativity of the two atoms is necessary for the formation of an Ionic bond.

(iii) There must be an overall decrease in energy i.e., energy must be released.

For this an atom should have low value of Ionisation potential and the other atom should have high value of electron affinity.

(iv) Higher the lattice energy, greater will be the case of forming an ionic compound.

Solution 4

It will form a cation: X3+

(i) X2(SO4)3

(ii) X(NO3)3

(iii) XPO4

(iv) X2(CO3)3

(v) X(OH)3

Solution 5

Atoms combine with other atoms to attain stable octet or noble gas configuration.

Solution 6

The crystalline solid is ionic in nature. It has strong electrostatic forces of attraction between its ions, which cannot be separated easily.

Crystalline solids have high melting and boiling points, and a large amount of energy is required to break the strong bonding force between ions.

Water is a polar compound, so it decreases the electrostatic forces of attraction in the crystalline solid, resulting in free ions in the aqueous solution. Hence, the solid dissolves.

Solution 7

X and Y form an ionic bond in XY2.

.

Solution 8

(a) X has 7 electrons in its outermost shell and Y has only one electron in its outermost shell so Y loses its one electron and X gains that electron to form an ionic bond.

(b) The formula of the compound would be XY.

Solution 9

Orbit structure and electron dot diagram of NaCl:

 

Orbit structure and electron dot diagram of MgCl2:

Orbit structure and electron dot diagram of CaO:

 

Solution 10

(a) Sodium atom and sodium ion

(i) Sodium atom has one electron in M shell while sodium ion has 8 electrons in L shell.

(ii) Sodium atom is neutral while sodium ion is positively charged.

(iii) Sodium atom is highly reactive while its ion is inert.

iv) Sodium atom is poisonous while sodium ion is non-poisonous.

(b)Chlorine atom and chlorine ion

(i) Chlorine atom has 7 electrons in its M shell while Chloride ion has 8 electrons in the same shell.

(ii) Chlorine atom is neutral while chloride ion is negatively charged.

(iii) Chlorine atom is highly reactive while its ion is inert.

iv) Chlorine gas is poisonous while chloride ion is non-poisonous.

Solution 11

Fluoride ion is negatively charged while neon atom is neutral.

Solution 12

a. Transfer of electron(s) is involved in the formation of an electrovalent bond. The electropositive atom undergoes oxidation, while the electronegative atom undergoes reduction. This is known as a redox process.

Oxidation: In the electronic concept, oxidation is a process in which an atom or ion loses electron(s).

 

Zn Zn2+ + 2e-

Reduction: In the electronic concept, the reduction is a process in which an atom or ion accepts electron(s).


Cu2+ + 2e- Cu

b.  


 i. Zn Zn2+ + 2e- (Oxidation)


 Pb2+ + 2e-   Pb (Reduction)


 ii. Zn Zn2+ + 2e- (Oxidation)


 Cu2+ + 2e- Cu (Reduction)


 iii. Cl2 + 2e-2Cl- (Reduction)


 2Br- Br2 + 2e- (Oxidation)


 iv. Sn2+ Sn4+ + 2e- (Oxidation)


 2Hg2+ + 2e- Hg2 (Reduction)


 v. Cu+ Cu2+ + e- (Oxidation)


Cu+ + e- Cu (Reduction)

 

c. 2K + Cl2 2KCl

 i. Oxidation: In the electronic concept, oxidation is a process in which an atom or ion loses electron(s).


 K K+ + e-

 ii. Reduction: In the electronic concept, the reduction is a process in which an atom or ion accepts electron(s).


 Cl2 + 2e- 2Cl-

 iii. Oxidising agent

 An oxidising agent oxidises other substances either by accepting electrons or by providing oxygen or an electronegative ion, or by removing hydrogen or an electropositive ion.


 Cl2 + 2e- 2Cl-

 iv. Reducing agent

 A reducing agent reduces other substances either by providing electrons or by providing hydrogen or an electropositive ion, or by removing oxygen or an electronegative ion.


 K K+ + e-

Concise Chemistry Part II - Selina Solution for Class 10 Chemistry Chapter 2 - Chemical Bonding Page/Excercise Intext 2

Solution 1

(i) Both atoms should have four or more electrons in their outermost shells, i.e., non-metals.

(ii) Both the atoms should have high electronegativity.

(iii) Both the atoms should have high electron affinity and high ionisation potential.

(iv) Electronegativity difference between the two atoms should be zero or negligible.

(v) The approach of the atoms towards one another should be accompanied by decrease of energy.

Solution 2

(a) A is a non-metal; B is a metal while C is a chemically inert element.

(b) BA

Solution 3 (2017)

a.  

   

b.  

 

c.    

 

Solution 4

(a) Ionic compounds are formed as a result of the transfer of one or more electrons from the atom of a metallic electropositive element to an atom of a non-metallic electronegative element.

A polar covalent compound is the one in which there is an unequal distribution of electrons between the two atoms.

(b) Ionic compounds, made up of ions, are generally crystalline solids with high melting and boiling points.

They are soluble in water and good conductors of electricity in aqueous solution and molten state.

Covalent compounds, made up of molecules, can exist as soft solids or liquids or gases with low melting and boiling points. They are generally insoluble in water and poor conductors of electricity.

(c) Polar covalent compounds are formed between 2 non-metal atoms that have different electronegativities and therefore have unequal sharing of the bonded electron pair.

Non-polar compounds are formed when two identical non-metals equally share electrons between them.

Solution 5

(a) X+

(b) X will be a strong reducing agent as it will have the tendency to donate its valence electron.

Solution 6

Covalent compounds are said to be polar when shared pair of electrons are unequally distributed between the two atoms. For example in HCl, the high electronegativity of the chlorine atom attracts the shared electron pair towards itself. As a result, it develops a slight negative charge and hydrogen atom develops a slight positive charge. Hence, a polar covalent bond is formed.

Solution 7

a.  

Atom

Electronic configuration

Nearest noble gas

To attain stable electronic configuration of a nearest noble gas

Carbon

126C [2,4]

Neon [2,8]

Carbon needs four electrons to complete the octet.

Hydrogen

11H [1]

Helium [2]

Hydrogen needs one electron to complete the duplet.

 

One atom of carbon shares four electron pairs, one with each of the four atoms of hydrogen.

 

  

 

  

Before combination

(4 [H] and 1 [C] atom)  

After combination (CH4 - Methane molecule)

 

 

b. Methane is a covalent compound and is non-polar in nature. This is because the shared pair of electrons is equally distributed between the two atoms. So, no charge separation takes place and the molecule is symmetrical and electrically neutral.

Solution 8

(a) Properties of Electrovalent Compounds:

1. Ionic compounds usually exist in the form of crystalline solids.

2. Ionic compounds have high melting and boiling points.

3. Ionic compounds are generally soluble in water but insoluble in organic solvents.

4. They are good conductors of electricity in the fused or in an aqueous solution state.


(b) Properties of Covalent Compounds:

1.The covalent compounds exist as gases or liquids or soft solids.

2. The melting and boiling points of covalent compounds are generally low.

3. Covalent compounds are insoluble in water but dissolve in organic solvents.

4. They are non-conductors of electricity in the solid, molten or aqueous state.

Solution 9

a.  

 i. Covalent bond

 ii. Polar covalent bond

 iii. Ionic bond

 

b. 

    i. water: Polar covalent bonding takes place in water.

     

    ii. calcium oxide: Electrovalent bonding takes place in calcium oxide.

 

Solution 10

a. Electrovalent compounds are good conductors of electricity in the fused or aqueous state because electrostatic forces of attraction between ions in the solid state are very strong and these forces weaken in the fused state or in the solution state. Hence, ions become mobile.

b. Electrovalent compounds have a strong force of attraction between the oppositely charged ions, so a large amount of energy is required to break the strong bonding force between ions. So, they have high boiling and melting points.

 Covalent compounds have weak forces of attraction between the binding molecules, thus less energy is required to break the force of binding. So, they have low boiling and melting points.

c. As water is a polar compound, it decreases the electrostatic forces of attraction, resulting in free ions in the aqueous solution. Hence, electrovalent compounds dissolve.

 Covalent compounds do not dissolve in water but dissolve in organic solvents. Organic solvents are non-polar; hence, these dissolve in non-polar covalent compounds.

d. Electrovalent compounds are usually hard crystals yet brittle because they have strong electrostatic forces of attraction between their ions which cannot be separated easily.

e. Polar covalent compounds conduct electricity because they form ions in their solutions.

Solution 11

a.  

 i. Y = 9

 ii. Z = 12

b. Ionic bond with molecular formula ZY2.

Solution 12

MgCl2 - Electrovalent compound

CCl4 - Covalent compound

They are hard crystalline solids consisting of ions.

These are gases or liquids or soft solids.

They have high melting and boiling points.

They have low melting and boiling points.

They conduct electricity in the fused or aqueous state.

They do not conduct electricity in the solid, molten or aqueous state.

These are soluble in inorganic solvents but insoluble in organic solvents.

These are insoluble in water but dissolve in organic solvents.

 

Solution 13

Potassium chloride is an electrovalent compound and conducts electricity in the molten or aqueous state because the electrostatic forces of attraction weaken in the fused state or in aqueous solution.

Polar covalent compounds like hydrogen chloride ionise in their solutions and can act as an electrolyte. So, both can conduct electricity in their aqueous solutions.

Solution 14

a. HCl and NH3

b.  

HCl + H2O H3O+ + Cl-

 NH3 + H2O NH4+ + OH-

Solution 15

Formula of compound when combined with sulphur - MSFormula of compound when combined with chlorine - MCl2

Solution 16

(a) 

 

(b) 

 

(c) If the compound formed between A and B is melted and an electric current is passed through the molten compound, then element A will be obtained at the cathode and B at the anode of the electrolytic cell.

Concise Chemistry Part II - Selina Solution for Class 10 Chemistry Chapter 2 - Chemical Bonding Page/Excercise 2

Solution 1

The bond formed between two atoms by sharing a pair of electrons, provided entirely by one of the combining atoms but shared by both is called a coordinate bond. It is represented by an arrow starting from the donor atoms and ending in the acceptor atom.

Conditions:

1. One of the two atoms must have at least one lone pair of electrons.

2. Another atom should be short of at least a lone pair of electrons.

The two lone pair of electrons in the oxygen atom of water is used to form coordinate bond with the hydrogen ion which is short of an electron resulting in the formation of the hydronium ion.

H2O + H+ H3O+ Over here the hydrogen ion accepts one lone pair of electrons of the oxygen atom of water molecule leading to the formation of a coordinate covalent bond.

Solution 1(2007)

(i) Ions

(ii) Electrons are shared between the atoms of two or more elements

(iii) Two

(iv) Magnesium is oxidized and chlorine is reduced

Solution 1(2008)

(a)

(i) D

(b)

(i) Covalent bond

(ii) Coordinate bond.

Solution 1(2009)

a. Ammonium chloride

b.  

 

 A single covalent bond is present.

Solution 1(2010)

a. Oxidation

b.  

 i. ionic bond

 ii. covalent and oordinate bond

 iii. covalent bond

Solution 1(2011)

a.  

 i. Sharing

 ii. high

 iii. nitrogen

b.  

c.  

HCl is a covalent compound formed by sharing one electron between chlorine and hydrogen. Because chlorine is more electronegative than hydrogen, the shared pair of electrons shifts towards the chlorine atom. So, a partial negative charge (δ-) develops on chlorine and a partial positive charge (δ+) develops on hydrogen. Hence, the covalent bond is polar in nature.

Solution 1(2012)

a.  

Covalent and coordinate bond

b. E = 19

F = 8

G= 17

Molecular formula: EG

Chemical bond: Ionic bond

Solution 1(2013)

a. Dative or coordinate bond

b. B Ammonium chloride

c. C Are insoluble in water

d.  

Carbon tetrachloride

Sodium chloride

It is insoluble in water but dissolves in organic solvents.

It is soluble in water but insoluble in organic solvents.

It is a non-conductor of electricity due to the absence of ions.

It does not conduct electricity in the solid state but conducts electricity in the fused or aqueous state.

 

 

Solution 1(2014)

a. B

b. D

c. Ionisation

d. Their constituent particles are molecules. These exist as gases or liquids or soft solids because they have weak forces of attraction between their molecules.

Solution 2

A pair of electrons which is not shared with any other atom is known as a lone pair of electrons. It is provided to the other atom for the formation of a coordinate bond.

A pair of electrons which is shared between two atoms resulting in the formation of a covalent bond is called a shared pair.

Solution 3

a. Polar covalent bond

b. Ionic bond

c. O and H are bonded with a single covalent bond and oxygen possesses a single negative charge in the hydroxyl ion.

d. Covalent bond

e. Coordinate bond

f. Electrovalent bond, dative bond (or coordinate bond) and covalent bond

Solution 4

(a)

(i)

(ii)

(iii)

(b)

(i) Ammoniumion and hydronium ion

(ii) Phosphoruspentachloride and diamond

(iii) Hydrogen chloride and water vapour

(iv) Oxygen gas and nitrogen gas

(v) Toluene and Gasoline

Solution 5

Mg

Solution 6

 

Sodium

Phosphorus

Carbon

Formula of chloride

NaCl

PCl5

CCl4

Nature of bonding

Ionic

Covalent

Covalent

Physical state of chloride

Solid

Solid

Liquid

Solution 7

a. CaO - 1 calcium atom + 1 oxygen atom

Cl2 - 2 chlorine atoms

H2O - 2 hydrogen atoms + 1 oxygen atom

CCl4 - 1 carbon atom + 4 chlorine atoms

b. 

Ca - will donate two electrons

O - will accept two electrons

Cl - will accept one electron, so two Cl atoms will share an electron pair.

C - will accept four electrons by sharing electrons pairs with hydrogen forming covalent bonds.

H - will donate one electron by sharing an electron pair with carbon.

Solution 8

(a) Unequal,polar

(b) Middle, equally

(c) Electrovalent, electrostatic

Solution 9

a.  

 i. C

 ii. C

 iii. D

b.  

 i. Y is getting reduced.

 ii. Y is positive and it will migrate towards negative electrode that is cathode.

Solution 10

a.  

   

b. It is a non-polar covalent compound and does not dissolve in polar solvents like water.

c. Solid

d. No, in the formation of an ionic compound, one element is a metal and the other is a non-metal.

e. B

f. A

TopperLearning provides step-by-step solutions for each question in each chapter. Access Chapter 2 - Chemical Bonding  for ICSE Class 10 Chemistry free of cost. The solutions are provided by our subject matter experts. Refer to our solutions for the Selina Concise Chemistry textbook to revise the whole chapter and clear your fundamentals before the examination. By referring to the solutions for this chapter and the others, we hope that you are able to write your exams well. 

Text Book Solutions

ICSE X - Chemistry

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