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Concise Chemistry Part II - Selina Solution for Class 10 Chemistry Chapter 4 - Analytical Chemistry: Uses Of Ammonium Hydroxide And Sodium Hydroxide

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Selina Textbook Solutions Chapter 4 - Analytical Chemistry: Uses Of Ammonium Hydroxide And Sodium Hydroxide

Selina Textbook Solutions are a perfect way to ace your examination with high marks. These Textbook Solutions are extremely helpful for solving difficult questions in the ICSE Class 10 Chemistry exam. Our Selina Textbook Solutions are written by our subject experts. Find all the answers to the Selina textbook questions of Chapter 4 - Analytical Chemistry: Uses Of Ammonium Hydroxide And Sodium Hydroxide.

All Selina textbook questions of Chapter 4 - Analytical Chemistry: Uses Of Ammonium Hydroxide And Sodium Hydroxide solutions are created in accordance with the latest ICSE syllabus. These free Textbook Solutions for ICSE Class 10 Selina Concise Chemistry will give you a deeper insight on the fundamentals in this chapter and will help you to score more marks in the final examination. ICSE Class 10 students can refer to these solutions while doing their homework and while studying and revising for the Chemistry exam.

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Concise Chemistry Part II - Selina Solution for Class 10 Chemistry Chapter 4 - Analytical Chemistry: Uses Of Ammonium Hydroxide And Sodium Hydroxide Page/Excercise Intext 1

Solution 1

(i) Analysis: The determination of chemical components in a given sample is called analysis.

(ii) Qualitative analysis: The analysis which involves the identification of the unknown substances in a given sample is called qualitative analysis.

(iii) Reagent:A reagent is a substance that reacts with another substance.

(iv) Precipitation: It is the process of formation of an insoluble solid when solutions are mixed. The solid thus formed is called precipitate.

Solution 2

(i) Yellow

(ii) Colourless

(iii) PaleGreen

(iv) Colourless

Solution 3

 i. Pb2+

 ii. Cu2+

Solution 4

Name of solution

Soluble metal hydroxides

Insoluble metal hydroxides

Caustic soda solution

 

Zn(OH)2 Pb(OH)2

Fe(OH)3

Ammonium hydroxide solution

Zn(OH)2

Cu(OH)2

Fe(OH)3

Fe(OH)2

Solution 5

When ammonium salt is heated with caustic soda solution, ammonia gas is evolved.

The word equation is:

Ammonium chloride + Sodium hydroxide  Sodium chloride + water + ammonia


Ammonium sulphate + Sodium hydroxide    Sodium sulphate + water + ammonia

 

  

The balance equation is:

NH4Cl+NaOHNaCl+H2O+NH3

(NH4)2SO4 + 2NaOH Na2SO4 + 2H2O + 2NH3

Solution 6

NH4OH and NaOH can be distinguished by using calcium salts.

For example on adding NaOH to Ca(NO3)2, Ca(OH)2 is obtained as white precipitate which is sparingly soluble in excess of NaOH.

Ca(NO3)2+2NaOHCa(OH)2+2NaNO3

On addition of NH4OH to calcium salts, no precipitation of Ca(OH)2 occurs even with the addition of excess of NH4OH.This is because the concentration of OH- ions from the ionization of NH4OH is so low that it cannot precipitate the hydroxide of calcium.

Solution 7

If an alkali is added too quickly, then it is easy to miss a precipitate which redissolves in excess alkali.

Concise Chemistry Part II - Selina Solution for Class 10 Chemistry Chapter 4 - Analytical Chemistry: Uses Of Ammonium Hydroxide And Sodium Hydroxide Page/Excercise 4

Solution 1

(a) Ferrous salts: Light green

(b) Ammoniumsalts: Colourless

(c) Cupric salts: Blue

(d) Calcium salts: Colourless

(e) Aluminium salts: Colourless

Solution 2

(a) Cu(OH)2

(b) ZnO

(c) NaOH

(d) NH4OH

(e) Na+, Ca2+

(f) Fe2+, Mn2+

(g) Aluminium

(h) Zn(OH)2 and Al(OH)3

(i) PbO

(j) Ammonium ion

Solution 3

Solution 4

(i)

(ii)

(iii)

Solution 5

Solution 6

Zinc chloride (ZnCl2) is soluble in excess of ammonium hydroxide.

Solution 7

(a) ZnCl2

(b) Zn(OH)2

Solution 8

(a) PbO

(b) ZnO

(c) K2ZnO2

Solution 9

(a) (iii)

Aqueous solution of copper sulphate is blue.

(b) (iii)

 FeSO4 + 2NaOH  Fe(OH)2 + Na2SO4

  (Dirty green, (Colourless)

  gelatinous ppt.)

(c) (iii)

 Zn + 2NaOH  Na2ZnO2 + H2

 Sodium zincate

   (Colourless)

Zz Zn + HCl → ZnCl2 + H2 

Solution 10

When freshly precipitated aluminum hydroxide reacts with caustic soda solution, whitesalt of sodium meta aluminate is obtained.

Solution 11

Reagent bottles A and B can identified by using calcium salts such as Ca(NO3)2.

On adding NaOH to Ca (NO3)2, Ca (OH) 2 is precipitated as white precipitate which is sparingly soluble in excess of NaOH.

Ca(NO3)2+2NaOHCa(OH)2+2NaNO3

Whereas, on addition of NH4OH to calcium salts, no precipitation of Ca(OH)2 occurs even with addition of excess of NH4OH because the concentration of OH-ions from the ionization of NH4OH is so low that it cannot precipitate the hydroxide of calcium.

So the reagent bottle which gives white precipitate is NaOH and the other is NH4OH.

Solution 12

(a) Distinguish by adding Sodium hydroxide solution:

 

(i) Ca(NO3)2+2NaOHCa(OH)2+2NaNO3

On adding excess of NaOH, ppt. of Ca (OH)2is sparingly soluble.

Pb(NO3)2+2NaOHPb(OH)2+2NaNO3

On adding excess of NaOH, ppt of Pb(OH)2is soluble.

(ii) Pb(NO3)2+2NaOHPb(OH)2+2NaNO3

On adding excess of NaOH, ppt of Pb(OH)2is soluble.

ZnSO4+ 2NaOHZn(OH)2+ Na2SO4

With excess of NaOH, white gelatinous ppt. of Zn (OH)2 is soluble. So, these two cannot be distinguished by NaOH alone. However white ppt. of Pb(OH)2is readily soluble in acetic acid also.

(iii) CuSO4+2NaOHCu(OH)2+Na2SO4

With excess of NaOH, alkali pale blue ppt of Cu (OH)2is insoluble.

FeSO4+2NaOHFe(OH)2+ Na2SO4

With excess of NaOH, dirty green ppt. of Fe(OH)2 is insoluble.

(iv) FeSO4+2NaOHFe(OH)2 + NaSO4

With excess of NaOH, dirty green ppt of Fe(OH)2 is insoluble.

FeCl3+3NaOHFe(OH)3+3NaCl

With excess of NaOH, reddish brown ppt of Fe(OH)3 is insoluble.

(b) Distinguish by adding Ammonium hydroxide solution:

 

(i) On addition of NH4OH to calcium salts no precipitation of Ca(OH)2 occurs even with addition of excess of NH4OH because the concentration of OH-ions from ionization of NH4OH is so low that it cannot precipitate the hydroxide of calcium.

Pb(NO3)2+2 NH4OHPb(OH)2+2NH4NO3

On adding excess of NH4OH, chalky white ppt. of Pb(OH)2is insoluble.

(ii) Pb(NO3)2+2 NH4OHPb(OH)2+2NH4NO3

On adding excess of NH4OH, chalky white ppt. of Pb(OH)2is insoluble.

ZnSO4+2NH4OHZn(OH)2+(NH4)2SO4

With excess of NH4OH, white gelatinous ppt. of Zn(OH)2is soluble.

(iii) CuSO4+2NH4OHCu(OH)2+(NH4)2SO4

With excess of NH4OH, pale blue ppt. of Cu(OH)2is soluble.

FeSO4+2NH4OHFe(OH)2+(NH4)2SO4

With excess of NH4OH, dirty green ppt. of Fe (OH)2 is insoluble.

(iv) FeSO4+2NH4OHFe(OH)2+(NH4)2SO4

With excess of NH4OH, dirty green ppt. of Fe (OH)2 is insoluble.

FeCl3+3NH4OHFe(OH)3+3NH4Cl

With excess of NH4OH, reddish brown ppt of Fe (OH)3 is insoluble.

Solution 13

Lead carbonate is dissolved in dilute nitric acid and then ammonium hydroxide is added to it. A white precipitate is formed which is insoluble in excess.

Zinc carbonate is dissolved in dilute nitric acid and then ammonium hydroxide is added to it. A white precipitate is formed which is soluble in excess.

Solution 14

a. Zn + 2NaOH Na2ZnO2 + H2

b. 2Al + 2NaOH + 2H2O 2Na2AlO2 + 3H2

Solution 15

a. Amphoteric oxides are compounds which react with both acids and alkalis to form salt and water.

b. ZnO + 2NaOH Na2ZnO2 + H2O

 Al2O3 + 2NaOH 2NaAlO2 + H2O

c. Sodium zincate

Aluminium zincate

Solution 16

TopperLearning provides step-by-step solutions for each question in each chapter. Access Chapter 4 - Analytical Chemistry: Uses Of Ammonium Hydroxide And Sodium Hydroxide  for ICSE Class 10 Chemistry free of cost. The solutions are provided by our subject matter experts. Refer to our solutions for the Selina Concise Chemistry textbook to revise the whole chapter and clear your fundamentals before the examination. By referring to the solutions for this chapter and the others, we hope that you are able to write your exams well. 

Text Book Solutions

ICSE X - Chemistry

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