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Frank Modern Certificate Solution for Class 10 Chemistry Chapter 5 - Mole Concept And Stoichiometry

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Frank Textbook Solutions Chapter 5 - Mole Concept And Stoichiometry

Frank Textbook Solutions are considered extremely helpful for solving difficult questions in the ICSE Class 10 Chemistry exam. TopperLearning Textbook Solutions are compiled by our subject experts. Herein, you can find all the answers to the questions of   Chapter 5 - Mole Concept And Stoichiometry for the Frank textbook.

Frank Textbook Solutions for class 10 are in accordance with the latest ICSE syllabus, and they are amended from time to time to be most relevant. Our free Frank Textbook Solutions for ICSE Class 10 Chemistry will give you deeper insight on the chapters and will help you to score more marks in the final examination. ICSE Class 10 students can refer to our solutions while doing their homework and while preparing for the exam.

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Exercise/Page

Frank Modern Certificate Solution for Class 10 Chemistry Chapter 5 - Mole Concept And Stoichiometry Page/Excercise 103

Solution 1

(a) Gay-Lussac's law: It states that 'when gases react, they do so in volumes which bear a simple ratio to one another, and also to the volume of the gaseous product, provided all the volumes are measured at the same temperature and pressure'.
(b) Avogadro's law : It states that 'Under the same conditions of temperature and pressure, equal volumes of all gases contain the same number of molecules'.

Solution 2

Solution 3

When stating the volume of a gas, the pressure and temperature should also be given because the volume of a gas is highly susceptible to slight change in pressure and temperature of the gas.

Solution 4


Solution 5

Solution 6

Solution 7

(a) Gram atom: "The quantity of the element which weighs equal to its gram atomic mass is called one gram atom of that element".
For example: The gram atomic mass of hydrogen is 1g. So, 1g of hydrogen is 1 gram atom of hydrogen.
(b) Gram mole: "A sample of substance with its mass equal to its gram molecular mass is called one gram molecule of this substance or one gram mole".
For example: Gram molecular mass of oxygen is 32 g. So One gram mole of oxygen is 32g.

Solution 8

Solution 9

Empirical formula:"Empirical formula of a compound is the formula which gives the number of atoms of different elements present in one molecule of the compound, in the simplest numerical ratio".
Molecular formula: "Molecular formula of a compound denotes the actual number of atoms of different elements present in one molecule of the compound".

Solution 10

(a) The empirical formula of C6H6 is: CH
(b) The empirical formula of C6H12O6 is: CH2O.
(c) The empirical formula of C2H2 is: CH
(d) The empirical formula of CH3COOH is: CH2O.

Solution 11

Three pieces of information conveyed by the formula H2O is that:

It shows that there are 2hydrogen atoms and 1oxygen atoms present in H2O.
The hydrogen and oxygen atoms are present in simplest whole number ratio of 2:1.
It represents one molecule of compound water.

Solution 12

Solution 13

Frank Modern Certificate Solution for Class 10 Chemistry Chapter 5 - Mole Concept And Stoichiometry Page/Excercise 104

Solution 14

Solution 15

(a) Na2SO4.10H2O.
(b) C6H12O6.

Solution 16

Solution 17

Solution 18

Solution 19

Solution 20

Solution 21

Solution 22

Solution 23

Solution 24

Frank Modern Certificate Solution for Class 10 Chemistry Chapter 5 - Mole Concept And Stoichiometry Page/Excercise 105

Solution 25

Solution 26


Solution 27

Solution 28

Solution 29

Solution 30

Solution 31

Solution 1996-1

Solution 1996-2

Solution 1996-3

Solution 1996-4

Frank Modern Certificate Solution for Class 10 Chemistry Chapter 5 - Mole Concept And Stoichiometry Page/Excercise 106

Solution 1997-1

Solution 1997-2

Solution 1997-3

Solution 1997-4

Solution 1998-1

Solution 1998-2

Solution 1999-1

Frank Modern Certificate Solution for Class 10 Chemistry Chapter 5 - Mole Concept And Stoichiometry Page/Excercise 107

Solution 1999-2


Solution 1999-3

Solution 2000-2

Solution 2000-1


Solution 2001-1

Gay - Lussac proposed this law.

Solution 2001-2

Molecular mass of ethane = 30
According to Gay-Lussac's law:
2 vol. of C2H6 requires= 7 vol. of oxygen
Vol. of C2H6 = 2 vol. = 100 L
Vol. of oxygen required = 7 vol. =350 L

Solution 2001-3

Frank Modern Certificate Solution for Class 10 Chemistry Chapter 5 - Mole Concept And Stoichiometry Page/Excercise 108

Solution 2001-4

The term is vapour density.

Solution 2001-5

Solution 2001-6

Solution 2001-7

Solution 2002-1


Solution 2002-2

Solution 2002-3

Solution 2003-1

Solution 2004-1

Frank Modern Certificate Solution for Class 10 Chemistry Chapter 5 - Mole Concept And Stoichiometry Page/Excercise 109

Solution 2004-2

Solution 2005-1

Solution 2006-1


Solution 2006-2

Frank Modern Certificate Solution for Class 10 Chemistry Chapter 5 - Mole Concept And Stoichiometry Page/Excercise 110

Solution 2006-3

Solution 2006-4

Solution 2007-1

Solution 2007-2

Solution 2008-1

The gas laws which relates the volume of a gas to the number of molecules of the gas is avogadro's law

Frank Modern Certificate Solution for Class 10 Chemistry Chapter 5 - Mole Concept And Stoichiometry Page/Excercise 111

Solution 2008-2

Solution 2008-3


Solution 2009-2

Solution 2009-3

The correct statement is that equal volumes of all gases under identical conditions contain the same number of molecules.

Solution 2009-4

Solution 2009-1

The relative molecular mass of the gas is 10.

TopperLearning provides step-by-step solutions for each question in each chapter in the Frank textbook recommended by ICSE schools. Access Chapter 5 - Mole Concept And Stoichiometry here. Our Frank Textbook Solutions for ICSE Class 10  Chemistry are designed by our subject matter experts. These solutions will help you to revise the whole chapter, so you can clear your fundamentals before the examination.

Text Book Solutions

ICSE X - Chemistry

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