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NCERT Solution for Class 9 Chemistry Chapter 3 - Atoms and Molecules

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NCERT Textbook Solutions are considered extremely helpful when preparing for your CBSE Class 9 Chemistry exams. TopperLearning study resources infuse profound knowledge, and our Textbook Solutions compiled by our subject experts are no different. Here you will find all the answers to the NCERT textbook questions of Chapter 3 - Atoms and Molecules.

All our solutions for Chapter 3 - Atoms and Molecules are prepared considering the latest CBSE syllabus, and they are amended from time to time. Our free NCERT Textbook Solutions for CBSE Class 9 Chemistry will strengthen your fundamentals in this chapter and can help you to score more marks in the examination. Refer to our Textbook Solutions any time, while doing your homework or while preparing for the exam.

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NCERT Solution for Class 9 Chemistry Chapter 3 - Atoms and Molecules Page/Excercise 32

Solution 1

The reactants in this reaction are sodium carbonate and ethanoic acid and the products are carbon dioxide, water and sodium ethanoate.
The total mass of the reactants = 5.3 + 6 = 11.3 g
The total mass of the products = 2.2 + 0.9 + 8.2 = 11.3 g
Thus, the total mass of the reactants is same as that of the products. Thus, the mass was neither created nor destroyed during the chemical reaction. Therefore, the mass was conserved during the reaction of sodium carbonate and ethanoic acid.   Concept insight: Firstly, recall the law of conservation of mass. And then check whether it is being followed by the data which is given or not.

NCERT Solution for Class 9 Chemistry Chapter 3 - Atoms and Molecules Page/Excercise 33

Solution 2

The law of constant proportions states that in a chemical substance, the elements are always present in definite proportions by mass. Hydrogen and oxygen combine in the ratio of 1:8 by mass to form water.   1g of hydrogen reacts with oxygen = 8g   Thus, in order to form water, 3 x 8 = 24 g of oxygen will react completely with 3 g of hydrogen gas.

Concept insight: Recall the law of constant proportions and then apply that in a chemical substance, the elements are always present in definite proportions by mass.

Solution 3

The second postulate of Dalton's atomic theory which states that "Atoms are indivisible particles, which cannot be created or destroyed in a chemical reaction" is the result of the law of conservation of mass.

Concept insight: For answering this question you should know both the law of conservation of mass and the postulates of Dalton's atomic theory.

Solution 4

The postulate of Dalton's atomic theory which states that "The relative number and kinds of atoms are constant in a given compound" can explain the law of definite proportions.

Concept insight: For answering this question, you should know both law of definite proportions and the postulates of Dalton's atomic theory.

NCERT Solution for Class 9 Chemistry Chapter 3 - Atoms and Molecules Page/Excercise 35

Solution 1

Atomic mass unit is a mass unit equal to exactly one-twelfth the mass of a carbon-12 atom. It is used to measure the masses of subatomic particles.

Concept insight: In this answer, write the proper definition of atomic mass unit.

Solution 2

The dimension of atoms is very, very small and is of the order of 1 nm. Thus, we cannot see an atom with naked eyes.
 
Concept insight: For answering this question, you should recall the size of an atom.


NCERT Solution for Class 9 Chemistry Chapter 3 - Atoms and Molecules Page/Excercise 39

Solution 1



Concept insight: For answering this question, write the cation and anion with the proper charges, cross multiply and write the formula.

Solution 2

(i) Aluminium sulphate
(ii) Calcium chloride
(iii) Potassium sulphate
(iv) Potassium nitrate
(v) Calcium carbonate   Concept insight: For writing the name of the compound, write the name of the cation first and then the anion.

Solution 3

The chemical formula of a compound is a symbolic representation of its composition.   Concept insight: For this question, write the proper definition of chemical formula.

Solution 4

(i) Three (Two hydrogen atoms and one sulphur atom)
(ii) Five (One phosphorus and four oxygen)

Concept insight: Count the total number of atoms of each type and add them.

NCERT Solution for Class 9 Chemistry Chapter 3 - Atoms and Molecules Page/Excercise 40

Solution 1

Molecular mass of H2 = Mass of 2H atoms = 1u + 1u = 2u
Molecular mass of O2 = Mass of 2O atoms = 16u + 16u = 32u
Molecular mass of Cl2 = Mass of 2Cl atoms = 35.5u + 35.5u = 71u
Molecular mass of CO2 = Mass of C atom + 2 x Mass of O atom = 12u + (2 16u) = 44u
Molecular mass of CH4 = Mass of C atom + 4 x Mass of H atom = 12u + (4 1 u) = 16u
Molecular mass of NH3 = Mass of N atom + 3 x Mass of H atom = 14u + (3 1 u) = 17u
Molecular mass of CH3OH = Mass of C atom + 3 x Mass of H atom + Mass of O atom + Mass of H atom = 12u + (3 1 u) + 16 u + 1 u = 32u

Concept insight: For calculating the molecular mass, add the atomic masses of all the atoms present in the formula.

Solution 2

Formula unit mass of ZnO = 65 u + 16 u = 81 u
Formula unit mass of Na2O = (2 x 23 u) + 16 u = 62 u
Formula unit mass of K2CO3 = (2 x 39 u) + 12 u + (3 x 16 u) = 138 u   Concept insight: For calculating the formula unit mass, add the atomic masses of all the atoms present in the formula.

NCERT Solution for Class 9 Chemistry Chapter 3 - Atoms and Molecules Page/Excercise 42

Solution 1

1 mole = 6.022 x 1023 atoms One mole of carbon atoms weighs 12 gram.
 i.e. 6.022 x 1023 atoms of carbon weigh 12 gram.
Therefore,
1 atom of carbon weighs 12 / (6.022 x 1023) = 1.993 x 10-23 gram.

Concept insight: For answering questions related to mole concept apply the relation

Solution 2

  Concept insight: For answering questions related to mole concept, apply the relation  

NCERT Solution for Class 9 Chemistry Chapter 3 - Atoms and Molecules Page/Excercise 43

Solution 1

  Concept insight:   Always remember,  

Solution 2

3.0 g of carbon combines with 8.0 g of oxygen to give 11.0 of carbon dioxide.
Thus, by the law of definite proportions, when 3.00 g of carbon is burnt in 50.00 g of oxygen, only 8.00 g of oxygen will be used to produce 11.00 gram of carbon dioxide. The remaining 42.00 g of oxygen will remain unreacted. Law of constant proportion is governed.

Concept insight: Relate the given data in the question to the laws and then identify which law is governing the answer.

NCERT Solution for Class 9 Chemistry Chapter 3 - Atoms and Molecules Page/Excercise 44

Solution 3

Polyatomic ions are those ions that are formed from groups of joined atoms. These atoms can be of the same type or of different type. Some examples of polyatomic ions are NO3-, NH4+, OH-, SO42-, and SO32-.

Concept insight: Recall the definition of polyatomic ions and give examples of it. It is an important question from exam point of view.

Solution 4

(a) MgCl2
(b) CaO
(c) Cu(NO3)2
(d) AlCl3
(e) CaCO3

Concept insight: For answering this question, write the cation and anion with the proper charges, cross multiply and write the formula.

Solution 5

(a) Calcium and oxygen
(b) Hydrogen and bromine
(c) Sodium, hydrogen, carbon, and oxygen
(d) Potassium, sulphur, and oxygen

Concept insight: For answering this question, write the formula of the compound first, see which all atoms are present in it and then write their names.

Solution 6

(a) Molecular mass of ethyne, C2H2 = 2 x Mass of C + 2 x Mass of H = 212u + 2u = 26u
(b) Molecular mass of sulphur molecule, S8 = 8 x Mass of S = 832u = 256u
(c) Molecular mass of phosphorus molecule, P4 = 4 x Mass of P = 431u = 124u
(d) Molecular mass of HCl = Mass of H + Mass of Cl = 1 u + 35.5u = 36.5u
(e) Molecular mass of HNO3 = Mass of H + Mass of N + 3 x Mass of O = 1 u + 14u + 316u = 63u

Concept insight: For calculating the molecular mass, add the atomic masses of all the atoms present in the formula.  

Solution 7

(a) Mass of one mole of nitrogen atoms = molecular mass of nitrogen atoms in grams = 14 g
(b) Mass of 4 moles of aluminium atoms = 4 x Mass of 1 mole of Al atoms = 4 x molecular mass of aluminum atoms in grams = 4 x 27 = 108 g
(c) Mass of 10 moles of sodium sulphite = 10 x Mass of 1 mole of Na2SO3 = 10 x molecular mass of Na2SO3 in grams
Molecular mass of sodium sulphite, Na2SO3 = 2 x 23 + 32 + 3 x 16 = 126 g
Thus, the mass of 10 moles of sodium sulphite = 10 x 126 = 1260 g

Concept insight: For answering questions related to mole concept, apply the relation
 
For an atom ,
1 mole =  Gram atomic mass = 6.0221023 atoms
For a molecule,
1 mole = Gram atomic mass = 6.0221023 molecules


Solution 8

    Concept insight: For answering questions related to mole concept, apply the relation:  

Solution 9

(a) The mass of 1 mole of oxygen atoms = 16 g
Thus, the mass of 0.2 mole of oxygen atoms = 16  0.2 = 3.2 g
(b) The mass of 1 mole of water molecules = 18 g
Thus, the mass of 0.5 mole of water molecules = 18  0.5 = 9.0 g

Concept insight: For answering questions related to mole concept, apply the relation:   For  an atom,
1 mole = Gram atomic mass = 6.0221023
For  a molecule,
1 mole = Gram molecule mass = 6.0221023

Solution 10

  Concept insight: For answering questions related to mole concept, apply the relation:   For  an atom,
1 mole = Gram atomic mass = 6.0221023
For  a molecule,
1 mole = Gram molecule mass = 6.0221023

Solution 11

  Concept insight: For answering questions related to mole concept, apply the relation:   For  an atom,
1 mole = Gram atomic mass = 6.0221023
For  a molecule,
1 mole = Gram molecule mass = 6.0221023

TopperLearning provides step-by-step solutions for each question in each chapter in the NCERT textbook. Access Chapter 3 - Atoms and Molecules here for free.

Our NCERT Solutions for Class 9 Chemistry are by our subject matter experts. These NCERT Textbook Solutions will help you to revise the whole chapter, and you can increase your knowledge of Chemistry. If you would like to know more, please get in touch with our counsellor today!

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