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NCERT Solution for Class 11 Science Physics Chapter 4 - Motion in a Plane

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NCERT Textbook Solutions are considered extremely helpful when preparing for your CBSE Class 11 Physics exams. TopperLearning study resources infuse profound knowledge, and our Textbook Solutions compiled by our subject experts are no different. Here you will find all the answers to the NCERT textbook questions of Chapter 4 - Motion in a Plane.

All our solutions for Chapter 4 - Motion in a Plane are prepared considering the latest CBSE syllabus, and they are amended from time to time. Our free NCERT Textbook Solutions for CBSE Class 11 Physics will strengthen your fundamentals in this chapter and can help you to score more marks in the examination. Refer to our Textbook Solutions any time, while doing your homework or while preparing for the exam.

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Exercise/Page

NCERT Solution for Class 11 Science Physics Chapter 4 - Motion in a Plane Page/Excercise 85

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Solution 2

Solution 3

Solution 4

(a)The addition of two scalar quantities is meaningful only if they both represent the same physical quantity.


(b)The addition of a vector quantity with a scalar quantity is not meaningful.

(c) Yes, multiplying a vector by scalar is perfectly meaningful and gives a vector
in output having magnitude scalar times the magnitude of original vector. For example, force is multiplied with time to give impulse.


(d) Yes , product of two scalars is meaningful. For example, V=IR, multiplies scalars current and resistance to give voltage.


(e)The addition is meaningful if both the vectors have same dimensions.

(f)Yes, as both the vectors have same dimensions they can be added to give a vector output.

Solution 5

Solution 6








NCERT Solution for Class 11 Science Physics Chapter 4 - Motion in a Plane Page/Excercise 86

Solution 7


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Solution 9


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Solution 11

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Solution 13

NCERT Solution for Class 11 Science Physics Chapter 4 - Motion in a Plane Page/Excercise 87

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Solution 23

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Solution 25


NCERT Solution for Class 11 Science Physics Chapter 4 - Motion in a Plane Page/Excercise 88

Solution 26


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Solution 29

begin mathsize 14px style Given colon
Range comma space straight R equals 3 space km
Angle space of space projection comma space straight theta equals 30 degree
Acceleration space due space to space gravity comma space straight g equals 9.8 space straight m divided by straight s squared
Horizontal space range space for space the space projection space velocity space straight u subscript 0 comma space is space given space by space the space relation colon
straight R equals fraction numerator straight u subscript 0 superscript 2 sin 2 straight theta over denominator straight g end fraction
3 equals fraction numerator straight u subscript 0 superscript 2 over denominator straight g end fraction sin 60 degree
square root of 3 cross times square root of 3 equals fraction numerator straight u subscript 0 superscript 2 over denominator straight g end fraction cross times fraction numerator square root of 3 over denominator 2 end fraction space space space space left square bracket because 3 equals square root of 3 cross times square root of 3 right square bracket
fraction numerator straight u subscript 0 superscript 2 over denominator straight g end fraction equals 2 square root of 3 space space space space space space... space left parenthesis 1 right parenthesis
The space maximum space range space left parenthesis straight R subscript max right parenthesis space is space achieved space by space bullet space when space it space is space fired space at space an space angle space of space 45 degree space with space the space horizontal comma space that space is comma
straight R subscript max equals fraction numerator straight u subscript 0 superscript 2 over denominator straight g end fraction space space space space space space space... space left parenthesis 2 right parenthesis
On space comparing space equations space left parenthesis 1 right parenthesis space and space left parenthesis 2 right parenthesis comma space we space get comma
straight R subscript max equals 2 square root of 3 equals 2 cross times 1.732 equals 3.46 space km
Hence comma space there space is space no space way space one space can space hope space to space hit space the space target space 5 space km space away. end style

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TopperLearning provides step-by-step solutions for each question in each chapter in the NCERT textbook. Access Chapter 4 - Motion in a Plane here for free.

Our NCERT Solutions for Class 11 Physics are by our subject matter experts. These NCERT Textbook Solutions will help you to revise the whole chapter, and you can increase your knowledge of Physics. If you would like to know more, please get in touch with our counsellor today!

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