Chapter 15 : Construction of Polygons (Using ruler and compass only) - Selina Solutions for Class 9 Maths ICSE

Mathematics in ICSE Class 9 is one of the most challenging and trickiest subjects of all. It includes complex topics such as logarithms, expansions, indices and Pythagoras Theorem which are difficult to understand for an average student. TopperLearning provides study materials for ICSE Class 9 Mathematics to make the subject easy and help students to clear all their concepts. Our study materials comprise numerous video lessons, question banks, revision notes and sample papers which help achieve success in the examination.

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Chapter 15 - Construction of Polygons (Using ruler and compass only) Excercise Ex. 15

Question 1

Construct a quadrilateral ABCD, when:

AB = 3.2 cm, BC = 5.2 cm, CD = 6.2 cm, DA = 4.2 cm and BD = 5.2 cm.

Solution 1

Steps:

1. Draw  .

2. With A as a centre draw an arc at D and with B as a centre and radius 5.2 cm draw an arc at D.

3. join AD and DB.

4. With D and b as a centre taking radius 6.2 cm and 5.2 cm draw arc at C. Now join BC and DC.

ABCD is the required quadrilateral.

Question 2

Construct a quadrilateral ABCD, when:

AB = 7.2 cm, BC = 5.8 cm, CD = 6.3 cm, AD = 4.3 cm and angle A = 75o.

Solution 2

Steps:

1. Draw  .

2. Through A draw AP such that  .

3. From AP cut

4. With D and B as centre and radii 6.2 cm and 5.8 cm respectively, draw arcs cutting each other at C.

5. Join DC and BC.

ABCD is the required quadrilateral.

Question 3

Construct a quadrilateral ABCD, when:

Angle A = 90o, AB = 4.6 cm, BD = 6.4 cm, AC = 6.0 cm and CD = 4.2 cm.

Solution 3

Steps:

1. Draw AB = 4.6 cm 

2. Through A, draw AP such that Angle A = 90°.

3. With B as a centre and radii 6.4 cm draw an arc at D on AP.

4. With D and A as a centre and radii 4.2 cm and 6 cm draw arc cutting each other at C.

5. Now join BD, AC and CB.

ABCD is the required quadrilateral.

Question 4

Construct a quadrilateral ABCD, when:

AB = 3.8 cm, AC = 4.8 cm, AD = 2.8 cm, angle A = 105o and angle B = 60o.

Solution 4

Steps:

1. Draw

2. Draw  and  .

3. draw BP such that  .

4. With A as a centre and radii 4.8 cm draw an arc cutting BP at C.

5. Join AC,AD.

ABCD is the required quadrilateral.

Question 5

Construct a quadrilateral ABCD, when:

BC = 7.5 cm AC = 5.8 cm, AD = 3.6 cm, CD = 4.2 cm and angle A = 120o.

Solution 5

Steps:

1. Draw

2. draw AP such that  .

3. With A and D as a centre and radii 5.8 cm and 4.2 cm draw arcs cutting each other at C.

4. Now join AC and CD.

5. Now with C as centre and radii 7.5 cm draw an arc at B on AP.

6. Now join CB.

ABCD is the required quadrilateral.

Question 6

Construct a quadrilateral ABCD, when:

AD = AB = 4 cm, BC = 2.8 cm, CD = 2.5 cm and angle BAD = 45o.

Solution 6

Steps:

1. Draw

2. Draw AP such that  .

3. With A as a centre with radii 4 cm draw an arc at B on AP.

4. Now taking B and D as a centre and radii 2.8 cm and 2.8 cm draw arcs cutting each other at C.

5. Now join BC and CD.

ABCD is the required quadrilateral.

Question 7

Construct a quadrilateral ABCD, when:

AB = 6.3 cm, BC = CD=4.2 cm and  ABC =  BCD = 90o.

Solution 7

Steps:

1. draw

2. Draw BP such that  .

3. With B as a centre and radii 4.2 cm draw an arc AP at C.

4. With C as a centre draw a line CD with radii 4.2 cm draw a line such that  .

5. Now join AD

ABCD is the required quadrilateral.

Question 8

Construct a parallelogram ABCD, when:

AB = 4.4 cm, AD = 6.2 cm and AC = 4.8 cm.

Solution 8

Steps:

1. Draw

2. Draw triangle ACD.

3. Then draw triangle ABC.

ABCD is the required parallelogram.

Question 9

Construct a parallelogram ABCD, when:

Diagonal AC = 6.4 cm, diagonals BD = 8.2 cm and angle between the diagonals = 60o.

Solution 9

Steps:

1. Draw

2. Draw line BOD such that  and

3. Join AB,BC,CD and DA.

ABCD is the required parallelogram.

Question 10

Construct a parallelogram ABCD, when:

AB = 5.8 cm, diagonal AC = 8.2 cm and diagonal BD = 6.2 cm.

Solution 10

Steps:

1. Since diagonal of a parallelogram bisect each other, construct OAB such that ;

And

2. Produce AO up to C, such that  and BO upto D, such that  .

3. Join AD,DC and CB.

ABCD is the required parallelogram.

Question 11

Construct a parallelogram ABCD, when:

AB = 6.0 cm, AD = 5.0 cm and  A = 45o.

Solution 11

Steps:

1. Draw

2. Draw AD with radii 5 cm with an angle of  .

3. With D and B as a centre and radii 6 cm and 5cm draw arcs cutting each other at C.

4. Now join DC and BC.

ABCD is the required parallelogram.

Question 12

Construct a parallelogram ABCD, when:

Base AB = 6.5 cm, BC = 4 cm and the altitude corresponding to AB = 3.1 cm.

Solution 12

Steps:

1. Draw

2. At B, draw

3. From BP cut  .

4. Through E draw perpendicular to BP to get QR parallel to AB.

5. With B as a centre and radius  ,draw an arc which cuts QR at C.

6. With A as a centre and radius  ,draw an arc which cuts QR at D.

ABCD is the required parallelogram.

Question 13

Construct a parallelogram ABCD, when:

AB = 4.5 cm,  B = 120o and the distance between AB and DC = 3.0 cm.

Solution 13

Steps:

1. Draw

2. At B, draw

3. From BP cut  .

4. Through E draw perpendicular to BP to get QR parallel to AB.

5. With B as a centre draw an arc which cuts QR at C.

6. With A as a centre draw an arc which cuts QR at D.

7. Now join Ad and BC.

ABCD is the required parallelogram.

Question 14

Construct a parallelogram ABCD, when:

Base BC = 5.6 cm, diagonal BD = 6.5 cm and altitude = 3.2 cm.

Solution 14

Steps:

1. Draw  .

2. At C, draw CX perpendicular to BC.

3. with C as a centre and taking radius 3.2 cm draw an arc to cut CX at Y.

4. Through Y draw a straight line PQ parallel to BC.

5. With B as a centre and radius 6.5 cm draw an arc to meet PQ at D.

6. With D as a centre and radius equal to 5.6 cm , draw an arc to meet PQ at A.

7. Join BA,BD and CD.

ABCD is the required parallelogram.

Question 15

Construct a rectangle ABCD, when:

Its sides are 6.0 cm and 7.2 cm.

Solution 15

Since each angle of a rectangle is  and opposite sides are equal. Therefore,

Steps:

1. Draw  .

2. with B as a centre draw a line BX taking as a

3. Now taking radius 6 cm draw an arc at A.

4. From point A draw a line AY parallel to BC.

5. With A as a centre taking radius 7.2 cm draw an arc at D.

6. Now join CD.

ABCD is the required rectangle.

Question 16

Construct a rectangle ABCD, when:

One side = 4 cm and one diagonal is 5 cm. Measure the length of other side.

Solution 16

Steps:

1. Draw  .

2. With C as a centre and radius 5 cm draw an arc at A.

3. Now join AB and AC.

4. With A as a centre draw an arc at D.

5. Now join AD and CD.

ABCD is the required rectangle.

Question 17

Construct a rectangle ABCD, when:

One diagonal = 6.0 cm and the acute angle between the diagonals = 45o.

Solution 17

Steps:

1. Draw  .

2. Draw right triangle ACB.

3. Draw right triangle ADB.

4. Join DC.

ABCD is the required rectangle.

Question 18

Construct a rectangle ABCD, when:

Area = 24 cm2 and base = 4.8 cm2.

Solution 18

Given that the base = 4.8 cm2 and Area =

We know that area of rectangle .

Therefore,

24 = 4.8 x height

Height= 5

With  and height  , the rectangle is shown below:

Steps:

1. Draw base  .

2. With A and B as a centre draw an arcs taking radius  at D and C.

3. Now join AD,BC and DC.

ABCD is the required rectangle.

Question 19

Construct a rectangle ABCD, when:

Area = 36 cm2 and height = 4.5 cm.

Solution 19

Given that the height = 4.5 cm and Area =

We know that area of rectangle .

Therefore,

36= base x 4.5

Base= 8 cm

With  and base  , the rectangle is shown below:

Steps:

1. Draw base  .

2. With A and B as a centre draw an arcs taking radius  at D and C.

3. Now join AD,BC and DC.

ABCD is the required rectangle.

Question 20

Construct a trapezium ABCD, when:

AB = 4.8 cm, BC = 6.8 cm, CD = 5.4 cm, angle B = 60o and AD // BC.

Solution 20

Steps:

1. Draw .

2. With B as a centre and radii 4.8 cm draw an arc at A such that  .

3. From point A draw a line AP such that  .

4. With C as a centre and radii 5.4 cm draw an arc at D on the line AP.

5. Now join AB,CD.

ABCD is the required trapezium.

Question 21

Construct a trapezium ABCD, when:

AB = CD = 3.2 cm, BC = 6.0 cm, AD = 4.4 cm and AD // BC.

Solution 21

Steps:

1. Draw  .

2. From BC cut  .

3. draw triangle DEC such that

 and  .

4. Taking B and D as a centre and radii 3.2 cm and 4.1 cm respectively, draw arcs cutting each other at A.

5. Join AB and AD.

ABCD is the required trapezium.

Question 22

Construct a rhombus ABCD, when:

Its one side = 6 cm and  A = 60o.

Solution 22

Steps:

1. Draw a line

2. At A, we construct .

3. From AP, we cut at D taking .

4. Through B, we draw .

5. through D, we draw  to cut BQ at C.

ABCD is the required rhombus.

Question 23

Construct a rhombus ABCD, when:

One side = 5.4 cm and one diagonals is 7.0 cm.

Solution 23

Steps:

1. We construct the segment  .

2. With A as a centre and radius 5.4 cm , we draw an arc extending on both sides of AC.

3. With C as centre and same radius as in step 2, we draw an arc extending on both sides of AC to cut the first arc at B and D.

4. Join AB,BC,CD and DA.

ABCD is the required rhombus.

Question 24

Construct a rhombus ABCD, when:

Diagonal AC = 6.3 cm and diagonal BD = 5.8 cm.

Solution 24

Steps:

1. Draw  .

2. Draw perpendicular bisector to AC which cuts AC at O.

3. From this perpendicular cut OD and OB such that,

4. Join AB,BC,CD and DA.

ABCD is the required rhombus.

Question 25

Construct a rhombus ABCD, when:

One side = 5.0 cm and height = 2.6 cm.

Solution 25

Steps:

1. Draw

2. At B, draw  .

3. From BP, cut

4. Through E draw perpendicular to CP to get QR parallel to AB.

5. With A and B as a centre and radii 5 cm draw arcs cutting QR at D and C.

ABCD is the required rhombus.

Question 26

Construct a rhombus ABCD, when:

 A = 60o and height = 3.0 cm.

Solution 26

Steps:

1. Draw a line AP.

2. Now draw a line AF such that  .

3. At S draw a perpendicular SE of length 3 cm such that it cut at AF at D.

4. Through D draw a line QR parallel to AP.

5. Now taking the radius same as AD draw an arc at B on AP.

6. Now through and B taking radius same as AD and AB draw arcs cutting each other at C.

7. Now join BC.

ABCD is the required rhombus.

Question 27

Construct a rhombus ABCD, when:

Diagonal AC = 6.0 cm and height = 3.5 cm.

Solution 27

Steps:

1. draw a line AP.

2. now draw  and

3. Now draw a line BC such that  .

4. Now at C draw a line CY parallel to AP.

5. At point C and A, taking radius same as AB draw arcs cutting each other at D.

6. Now join AD.

ABCD is the required rhombus.

Question 28

Construct a square ABCD, when:

One side = 4.5 cm.

Solution 28

Steps:

1. Draw a line segment

2. Draw  .

3. From AP cut off  .

4. With B as a centre and radius 4.5 cm draw an arc.

5. With D as centre and radius 4.5 cm draw another arc cutting the former arc at C.

6. Join BC and CD.

ABCD is the required square.

Question 29

Construct a square ABCD, when:

One diagonal = 5.4 cm.

Solution 29

We know that the diagonals of a square are equal and bisect each other at right angles.

Steps:

1. draw

2. Draw the right bisector XY of AC, meeting AC at O.

3. From O, set off  along OY and  along OX.

4. Join AB, BC, CD and DA.

ABCD is the required square.

Question 30

Construct a square ABCD, when:

Perimeter = 24 cm.

Solution 30

The perimeter of a square

Where a is the length of each side.

We have Perimeter = 24 cm.

Therefore,

Therefore the sides of the squares are of length 6 cm.

Steps:

1. Draw a line segment

2. Draw  .

3. From AP cut off  .

4. With B as a centre and radius 6 cm draw an arc.

5. With D as centre and radius 6 cm draw another arc cutting the former arc at C.

6. Join BC and CD.

ABCD is the required square.

Question 31

Construct a rhombus, having given one side = 4.8 cm and one angle = 75o.

Solution 31

Steps:

1.draw a line

2. At A Draw AX such that  .

3. With A as a centre and measurement equal to AB cut off an arc at D on AX.

4. Using same radius taking D and B as centers cut off arcs, which will intersect at C.

5. Join CD and CB.

ABCD is the required rhombus.

Question 32

Construct a regular hexagon of side 2.5 cm.

Solution 32

The length of side of regular hexagon is equal to the radius of its circumcircle.

Steps of construction:

1.  Draw a circle of radius 2.5 cm

2.  Taking any point A on the circumference of the circle as centre, draw arcs of same radii (i.e. 2.5 cm) which cut the circumference at B and F.

3.  With B and F as centres, again draw two arcs of same radii which cut the circumference at C and E respectively.

4.  With C or E as centre, draw one more arc of the same radius which cuts the circumference at point D.

In this way, the circumference of the circle is divided into six equal parts.

5.  Join AB, BC, CD, DE, EF and FA.

  

 

ABCDEF is the required regular hexagon. 

Question 33

Construct a regular hexagon of side 3.2 cm

Solution 33

The length of side of regular hexagon is equal to the radius of its circumcircle.

Steps of construction:

1.  Draw a circle of radius 3.2 cm

2.  Taking any point A on the circumference of the circle as centre, draw arcs of same radii (i.e. 3.2 cm) which cut the circumference at B and F.

3.  With B and F as centres, again draw two arcs of same radii which cut the circumference at C and E respectively.

4.  With C or E as centre, draw one more arc of the same radius which cuts the circumference at point D.

In this way, the circumference of the circle is divided into six equal parts.

5.  Join AB, BC, CD, DE, EF and FA.

  

 

ABCDEF is the required regular hexagon. 

Question 34

Using ruler and compasses only, construct the quadrilateral ABCD, having given AB = 5 cm, BC = 2.5 cm, CD = 6 cm. angle BAD = 90o and the diagonal AC = 5.5 cm.

Solution 34

Steps:

1. draw

2. Now draw  such that it is  .

3. Taking A and B as a centre and radius 2.5 cm and 5.5 cm draw arcs cuts off at C.

4. Now join BC and AC.

5. Taking C as a centre and radius 6 cm draw arcs at D on AX.

ABCD is the required quadrilateral.

Question 35

Using ruler and compasses only, construct a trapezium ABCD, in which the parallel sides AB and DC are 3.3 cm apart; AB = 4.5 cm, angle A = 120o BC = 3.6 cm and angle B is obtuse.

Solution 35

Steps:

1. Draw  .

2. now draw  and draw  such that  .

3. Through X draw draw a line QR which is parallel to AB which cuts AS at D.

4. Through B draw an arc taking radius 3.6 cm at C on PQ.

5. Join CB.

ABCD is the required trapezium.

Question 36

Using ruler and compasses only, construct the quadrilateral ABCD, having given AB = 5 cm, BC = 2.5 cm CD = 6 cm,  BAD = 90o and diagonal BD = 5.5 cm.

Solution 36

Steps:

1.Draw AB=5cm.

2. From A draw a line AY such that  .

3. Taking B as a centre with radius 5.5 cm draw an arc at D on AY.

4. With D and B as centre and radii 6 cm and 2.5 cm draw arcs cutting each other at C.

4. Join DC and BC.

ABCD is the required quadrilateral.

Question 37

Using ruler and compasses only, construct a parallelogram ABCD using the following data: AB = 6 cm, AD = 3 cm and  DAB = 45o. If the bisector of  DAB meets DC at P, prove that  APB is a right angle.

Solution 37

Steps:

1.draw AB=6cm.

2. With A as a centre draw a line AX such that  .

3. With A as a centre and radii 3 cm draw an arc on AD.

4. now with D and B as a centre and radii 6 cm and 3 cm draw arcs cutting each other at C.

5. Join DC and BC.

ABCD is the required parallelogram.

Here

Now,

 …… (i)

Also, considering  ,

 …… (ii)

Therefore, from (i) and (ii)

Hence proved.

Question 38

The perpendicular distance between the pair of opposite sides of a parallelogram are 3 cm and 4 cm, and one of its angles measures 60o. Using ruler and compasses only, construct the parallelogram.

Solution 38

 

 

Steps:

1. Draw a base line AQ.

2. From A take some random distance in compass and draw one are below and above the line. Now without changing the distance in compass draw one are below and above the line. These arcs intersect each other above and below the line. Draw the line passing through these intersecting points, you will get a perpendicular to the line AQ.

3 Take distance of 4 cm in compass and mark an arc on the perpendicular above the line. Draw a line parallel to line AQ passing through through this arc.

4. From point A measure an angle of 60 degree and draw the line which intersect above drawn line at some point label it as D.

 5. Using the procedure given in step 2 again draw a perpendicular to line AD.

6. Take distance of 3 cm in compass and mark an arc on the perpendicular above the line. Draw a line parallel to line AD passing through through this arc which intersect the line AQ at some point label it as B and to other line at point C.

ABCD is the required parallelogram.

Question 39

Draw parallelogram ABCD with the following data:

AB = 6 cm, AD = 5 cm and  DAB = 45o.

Let AC and DB meet in O and let E be the mid-point of BC. Join OE. Prove that:

(i) OE // AB (ii) OE =  AB.

Solution 39

To draw the parallelogram follows the steps:

· First draw a line AB of measure 6cm. Then draw an angle of measure  at point A such that  and AD = 5cm.

· Now draw a line CD parallel to the line AB of measure 6cm. Then join BC to construct the parallelogram as shown below:

Now it is given that E is the midpoint of BC. We join OE. Now we are to prove that OE || AB and  .

Since O is the midpoint of AC and E is the midpoint of BC, therefore the line is parallel to AB and

Question 40

Using ruler and compasses only, construct a rectangle each of whose diagonals measure 6 cm and the diagonals interest at an angle of 45o.

Solution 40

To draw the rectangle follows the steps:

(1) Firs draw a line AC of measure 6cm.

(2) Then draw the perpendicular bisector of AC through O.

(3) At O draw an angle of measure  . Then produce OD of measure 3cm and OB of measure 3cm each.

(4) Now join AD, AB, BC and CD to form the rectangle.

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