# Chapter 15 : Construction of Polygons (Using ruler and compass only) - Selina Solutions for Class 9 Maths ICSE

Mathematics in ICSE Class 9 is one of the most challenging and trickiest subjects of all. It includes complex topics such as logarithms, expansions, indices and Pythagoras Theorem which are difficult to understand for an average student. TopperLearning provides study materials for ICSE Class 9 Mathematics to make the subject easy and help students to clear all their concepts. Our study materials comprise numerous video lessons, question banks, revision notes and sample papers which help achieve success in the examination.

## Chapter 15 - Construction of Polygons (Using ruler and compass only) Excercise Ex. 15

Construct a quadrilateral ABCD, when:

AB = 3.2 cm, BC = 5.2 cm, CD = 6.2 cm, DA = 4.2 cm and BD = 5.2 cm.

Steps:

1. Draw .

2. With A as a centre draw an arc at D and with B as a centre and radius 5.2 cm draw an arc at D.

3. join AD and DB.

4. With D and b as a centre taking radius 6.2 cm and 5.2 cm draw arc at C. Now join BC and DC.

ABCD is the required quadrilateral.

Construct a quadrilateral ABCD, when:

AB = 7.2 cm, BC = 5.8 cm, CD = 6.3 cm, AD = 4.3 cm and angle A = 75^{o}.

Steps:

1. Draw .

2. Through A draw AP such that .

3. From AP cut

4. With D and B as centre and radii 6.2 cm and 5.8 cm respectively, draw arcs cutting each other at C.

5. Join DC and BC.

ABCD is the required quadrilateral.

Construct a quadrilateral ABCD, when:

Angle A = 90^{o}, AB = 4.6 cm, BD = 6.4 cm, AC = 6.0 cm and CD = 4.2 cm.

Steps:

1. Draw AB = 4.6 cm

2. Through A, draw AP such that Angle A = 90°.

3. With B as a centre and radii 6.4 cm draw an arc at D on AP.

4. With D and A as a centre and radii 4.2 cm and 6 cm draw arc cutting each other at C.

5. Now join BD, AC and CB.

ABCD is the required quadrilateral.

Construct a quadrilateral ABCD, when:

AB = 3.8 cm, AC = 4.8
cm, AD = 2.8 cm, angle A = 105^{o} and angle B = 60^{o}.

Steps:

1. Draw

2. Draw and .

3. draw BP such that .

4. With A as a centre and radii 4.8 cm draw an arc cutting BP at C.

5. Join AC,AD.

ABCD is the required quadrilateral.

Construct a quadrilateral ABCD, when:

BC = 7.5 cm AC = 5.8 cm,
AD = 3.6 cm, CD = 4.2 cm and angle A = 120^{o}.

Steps:

1. Draw

2. draw AP such that .

3. With A and D as a centre and radii 5.8 cm and 4.2 cm draw arcs cutting each other at C.

4. Now join AC and CD.

5. Now with C as centre and radii 7.5 cm draw an arc at B on AP.

6. Now join CB.

ABCD is the required quadrilateral.

Construct a quadrilateral ABCD, when:

AD = AB = 4 cm, BC = 2.8
cm, CD = 2.5 cm and angle BAD = 45^{o}.

Steps:

1. Draw

2. Draw AP such that .

3. With A as a centre with radii 4 cm draw an arc at B on AP.

4. Now taking B and D as a centre and radii 2.8 cm and 2.8 cm draw arcs cutting each other at C.

5. Now join BC and CD.

ABCD is the required quadrilateral.

Construct a quadrilateral ABCD, when:

AB = 6.3 cm, BC = CD=4.2
cm and ABC = BCD = 90^{o}.

Steps:

1. draw

2. Draw BP such that .

3. With B as a centre and radii 4.2 cm draw an arc AP at C.

4. With C as a centre draw a line CD with radii 4.2 cm draw a line such that .

5. Now join AD

ABCD is the required quadrilateral.

Construct a parallelogram ABCD, when:

AB = 4.4 cm, AD = 6.2 cm and AC = 4.8 cm.

Steps:

1. Draw

2. Draw triangle ACD.

3. Then draw triangle ABC.

ABCD is the required parallelogram.

Construct a parallelogram ABCD, when:

Diagonal AC = 6.4 cm,
diagonals BD = 8.2 cm and angle between the diagonals = 60^{o}.

Steps:

1. Draw

2. Draw line BOD such that and

3. Join AB,BC,CD and DA.

ABCD is the required parallelogram.

Construct a parallelogram ABCD, when:

AB = 5.8 cm, diagonal AC = 8.2 cm and diagonal BD = 6.2 cm.

Steps:

1. Since diagonal of a parallelogram bisect each other, construct OAB such that ;

And

2. Produce AO up to C, such that and BO upto D, such that .

3. Join AD,DC and CB.

ABCD is the required parallelogram.

Construct a parallelogram ABCD, when:

AB = 6.0 cm, AD = 5.0 cm
and A = 45^{o}.

Steps:

1. Draw

2. Draw AD with radii 5 cm with an angle of .

3. With D and B as a centre and radii 6 cm and 5cm draw arcs cutting each other at C.

4. Now join DC and BC.

ABCD is the required parallelogram.

Construct a parallelogram ABCD, when:

Base AB = 6.5 cm, BC = 4 cm and the altitude corresponding to AB = 3.1 cm.

Steps:

1. Draw

2. At B, draw

3. From BP cut .

4. Through E draw perpendicular to BP to get QR parallel to AB.

5. With B as a centre and radius ,draw an arc which cuts QR at C.

6. With A as a centre and radius ,draw an arc which cuts QR at D.

ABCD is the required parallelogram.

Construct a parallelogram ABCD, when:

AB = 4.5 cm, B = 120^{o} and the distance between AB and
DC = 3.0 cm.

Steps:

1. Draw

2. At B, draw

3. From BP cut .

4. Through E draw perpendicular to BP to get QR parallel to AB.

5. With B as a centre draw an arc which cuts QR at C.

6. With A as a centre draw an arc which cuts QR at D.

7. Now join Ad and BC.

ABCD is the required parallelogram.

Construct a parallelogram ABCD, when:

Base BC = 5.6 cm, diagonal BD = 6.5 cm and altitude = 3.2 cm.

Steps:

1. Draw .

2. At C, draw CX perpendicular to BC.

3. with C as a centre and taking radius 3.2 cm draw an arc to cut CX at Y.

4. Through Y draw a straight line PQ parallel to BC.

5. With B as a centre and radius 6.5 cm draw an arc to meet PQ at D.

6. With D as a centre and radius equal to 5.6 cm , draw an arc to meet PQ at A.

7. Join BA,BD and CD.

ABCD is the required parallelogram.

Construct a rectangle ABCD, when:

Its sides are 6.0 cm and 7.2 cm.

Since each angle of a rectangle is and opposite sides are equal. Therefore,

Steps:

1. Draw .

2. with B as a centre draw a line BX taking as a

3. Now taking radius 6 cm draw an arc at A.

4. From point A draw a line AY parallel to BC.

5. With A as a centre taking radius 7.2 cm draw an arc at D.

6. Now join CD.

ABCD is the required rectangle.

Construct a rectangle ABCD, when:

One side = 4 cm and one diagonal is 5 cm. Measure the length of other side.

Steps:

1. Draw .

2. With C as a centre and radius 5 cm draw an arc at A.

3. Now join AB and AC.

4. With A as a centre draw an arc at D.

5. Now join AD and CD.

ABCD is the required rectangle.

Construct a rectangle ABCD, when:

One diagonal = 6.0 cm
and the acute angle between the diagonals = 45^{o}.

Steps:

1. Draw .

2. Draw right triangle ACB.

3. Draw right triangle ADB.

4. Join DC.

ABCD is the required rectangle.

Construct a rectangle ABCD, when:

Area = 24 cm^{2} and base = 4.8 cm^{2}.

Given that the base = 4.8 cm^{2} and Area =

We know that area of rectangle.

Therefore,

24 = 4.8 x height

Height= 5

With and height , the rectangle is shown below:

Steps:

1. Draw base .

2. With A and B as a centre draw an arcs taking radius at D and C.

3. Now join AD,BC and DC.

ABCD is the required rectangle.

Construct a rectangle ABCD, when:

Area = 36 cm^{2} and height = 4.5 cm.

Given that the height = 4.5 cm and Area =

We know that area of rectangle.

Therefore,

36= base x 4.5

Base= 8 cm

With and base , the rectangle is shown below:

Steps:

1. Draw base .

2. With A and B as a centre draw an arcs taking radius at D and C.

3. Now join AD,BC and DC.

ABCD is the required rectangle.

Construct a trapezium ABCD, when:

AB = 4.8 cm, BC = 6.8
cm, CD = 5.4 cm, angle B = 60^{o} and AD // BC.

Steps:

1. Draw.

2. With B as a centre and radii 4.8 cm draw an arc at A such that .

3. From point A draw a line AP such that .

4. With C as a centre and radii 5.4 cm draw an arc at D on the line AP.

5. Now join AB,CD.

ABCD is the required trapezium.

Construct a trapezium ABCD, when:

AB = CD = 3.2 cm, BC = 6.0 cm, AD = 4.4 cm and AD // BC.

Steps:

1. Draw .

2. From BC cut .

3. draw triangle DEC such that

and .

4. Taking B and D as a centre and radii 3.2 cm and 4.1 cm respectively, draw arcs cutting each other at A.

5. Join AB and AD.

ABCD is the required trapezium.

Construct a rhombus ABCD, when:

Its one side = 6 cm and A = 60^{o}.

Steps:

1. Draw a line

2. At A, we construct.

3. From AP, we cut at D taking.

4. Through B, we draw.

5. through D, we draw to cut BQ at C.

ABCD is the required rhombus.

Construct a rhombus ABCD, when:

One side = 5.4 cm and one diagonals is 7.0 cm.

Steps:

1. We construct the segment .

2. With A as a centre and radius 5.4 cm , we draw an arc extending on both sides of AC.

3. With C as centre and same radius as in step 2, we draw an arc extending on both sides of AC to cut the first arc at B and D.

4. Join AB,BC,CD and DA.

ABCD is the required rhombus.

Construct a rhombus ABCD, when:

Diagonal AC = 6.3 cm and diagonal BD = 5.8 cm.

Steps:

1. Draw .

2. Draw perpendicular bisector to AC which cuts AC at O.

3. From this perpendicular cut OD and OB such that,

4. Join AB,BC,CD and DA.

ABCD is the required rhombus.

Construct a rhombus ABCD, when:

One side = 5.0 cm and height = 2.6 cm.

Steps:

1. Draw

2. At B, draw .

3. From BP, cut

4. Through E draw perpendicular to CP to get QR parallel to AB.

5. With A and B as a centre and radii 5 cm draw arcs cutting QR at D and C.

ABCD is the required rhombus.

Construct a rhombus ABCD, when:

A = 60^{o} and height = 3.0 cm.

Steps:

1. Draw a line AP.

2. Now draw a line AF such that .

3. At S draw a perpendicular SE of length 3 cm such that it cut at AF at D.

4. Through D draw a line QR parallel to AP.

5. Now taking the radius same as AD draw an arc at B on AP.

6. Now through and B taking radius same as AD and AB draw arcs cutting each other at C.

7. Now join BC.

ABCD is the required rhombus.

Construct a rhombus ABCD, when:

Diagonal AC = 6.0 cm and height = 3.5 cm.

Steps:

1. draw a line AP.

2. now draw and

3. Now draw a line BC such that .

4. Now at C draw a line CY parallel to AP.

5. At point C and A, taking radius same as AB draw arcs cutting each other at D.

6. Now join AD.

ABCD is the required rhombus.

Construct a square ABCD, when:

One side = 4.5 cm.

Steps:

1. Draw a line segment

2. Draw .

3. From AP cut off .

4. With B as a centre and radius 4.5 cm draw an arc.

5. With D as centre and radius 4.5 cm draw another arc cutting the former arc at C.

6. Join BC and CD.

ABCD is the required square.

Construct a square ABCD, when:

One diagonal = 5.4 cm.

We know that the diagonals of a square are equal and bisect each other at right angles.

Steps:

1. draw

2. Draw the right bisector *XY* of AC, meeting AC at O.

3. From O, set off along OY and along OX.

4. Join AB, BC, CD and DA.

ABCD is the required square.

Construct a square ABCD, when:

Perimeter = 24 cm.

The perimeter of a square

Where *a* is the length of each side.

We have Perimeter = 24 cm.

Therefore,

Therefore the sides of the squares are of length 6 cm.

Steps:

1. Draw a line segment

2. Draw .

3. From AP cut off .

4. With B as a centre and radius 6 cm draw an arc.

5. With D as centre and radius 6 cm draw another arc cutting the former arc at C.

6. Join BC and CD.

ABCD is the required square.

Construct a rhombus,
having given one side = 4.8 cm and one angle = 75^{o}.

Steps:

1.draw a line

2. At A Draw AX such that .

3. With A as a centre and measurement equal to AB cut off an arc at D on AX.

4. Using same radius taking D and B as centers cut off arcs, which will intersect at C.

5. Join CD and CB.

ABCD is the required rhombus.

Construct a regular hexagon of side 2.5 cm.

The length of side of regular hexagon is equal to the radius of its circumcircle.

Steps of construction:

1. Draw a circle of radius 2.5 cm

2. Taking any point A on the circumference of the circle as centre, draw arcs of same radii (i.e. 2.5 cm) which cut the circumference at B and F.

3. With B and F as centres, again draw two arcs of same radii which cut the circumference at C and E respectively.

4. With C or E as centre, draw one more arc of the same radius which cuts the circumference at point D.

In this way, the circumference of the circle is divided into six equal parts.

5. Join AB, BC, CD, DE, EF and FA.

ABCDEF is the required regular hexagon.

Construct a regular hexagon of side 3.2 cm

The length of side of regular hexagon is equal to the radius of its circumcircle.

Steps of construction:

1. Draw a circle of radius 3.2 cm

2. Taking any point A on the circumference of the circle as centre, draw arcs of same radii (i.e. 3.2 cm) which cut the circumference at B and F.

3. With B and F as centres, again draw two arcs of same radii which cut the circumference at C and E respectively.

4. With C or E as centre, draw one more arc of the same radius which cuts the circumference at point D.

In this way, the circumference of the circle is divided into six equal parts.

5. Join AB, BC, CD, DE, EF and FA.

ABCDEF is the required regular hexagon.

Using ruler and
compasses only, construct the quadrilateral ABCD, having given AB = 5 cm, BC
= 2.5 cm, CD = 6 cm. angle BAD = 90^{o} and the diagonal AC = 5.5 cm.

Steps:

1. draw

2. Now draw such that it is .

3. Taking A and B as a centre and radius 2.5 cm and 5.5 cm draw arcs cuts off at C.

4. Now join BC and AC.

5. Taking C as a centre and radius 6 cm draw arcs at D on AX.

ABCD is the required quadrilateral.

Using ruler and
compasses only, construct a trapezium ABCD, in which the parallel sides AB
and DC are 3.3 cm apart; AB = 4.5 cm,
angle A = 120^{o} BC = 3.6 cm and angle B is obtuse.

Steps:

1. Draw .

2. now draw and draw such that .

3.
Through *X* draw draw a line QR which
is parallel to AB which cuts AS at D.

4. Through B draw an arc taking radius 3.6 cm at C on PQ.

5. Join CB.

ABCD is the required trapezium.

Using ruler and
compasses only, construct the quadrilateral ABCD, having given AB = 5 cm, BC
= 2.5 cm CD = 6 cm, BAD = 90^{o} and diagonal BD = 5.5 cm.

Steps:

1.Draw AB=5cm.

2. From A draw a line AY such that .

3. Taking B as a centre with radius 5.5 cm draw an arc at D on AY.

4. With D and B as centre and radii 6 cm and 2.5 cm draw arcs cutting each other at C.

4. Join DC and BC.

ABCD is the required quadrilateral.

Using ruler and
compasses only, construct a parallelogram ABCD using the following data: AB =
6 cm, AD = 3 cm and DAB = 45^{o}. If the bisector of DAB meets DC at P, prove that APB is a right angle.

Steps:

1.draw AB=6cm.

2. With A as a centre draw a line AX such that .

3. With A as a centre and radii 3 cm draw an arc on AD.

4. now with D and B as a centre and radii 6 cm and 3 cm draw arcs cutting each other at C.

5. Join DC and BC.

ABCD is the required parallelogram.

Here

Now,

…… (i)

Also, considering ,

…… (ii)

Therefore, from (i) and (ii)

Hence proved.

The perpendicular distance between the pair of opposite sides of a parallelogram are 3 cm and 4 cm, and one of its angles measures 60^{o}. Using ruler and compasses only, construct the parallelogram.

Steps:

1. Draw a base line AQ.

2. From A take some random distance in compass and draw one are below and above the line. Now without changing the distance in compass draw one are below and above the line. These arcs intersect each other above and below the line. Draw the line passing through these intersecting points, you will get a perpendicular to the line AQ.

3 Take distance of 4 cm in compass and mark an arc on the perpendicular above the line. Draw a line parallel to line AQ passing through through this arc.

4. From point A measure an angle of 60 degree and draw the line which intersect above drawn line at some point label it as D.

5. Using the procedure given in step 2 again draw a perpendicular to line AD.

6. Take distance of 3 cm in compass and mark an arc on the perpendicular above the line. Draw a line parallel to line AD passing through through this arc which intersect the line AQ at some point label it as B and to other line at point C.

ABCD is the required parallelogram.

Draw parallelogram ABCD with the following data:

AB = 6 cm, AD = 5 cm and
DAB = 45^{o}.

Let AC and DB meet in O and let E be the mid-point of BC. Join OE. Prove that:

(i) OE // AB (ii) OE = AB.

To draw the parallelogram follows the steps:

·
First draw a line *AB *of measure 6cm. Then draw an angle of measure at point *A* such that and *AD *= 5cm.

·
Now draw a line *CD *parallel to the line *AB*
of measure 6cm. Then join *BC* to
construct the parallelogram as shown below:

__ __

Now
it is given that *E* is the midpoint
of *BC*. We join *OE*. Now we are to prove that *OE*
|| *AB* and .

Since *O* is the midpoint of *AC* and *E* is the midpoint of *BC*,
therefore the line is parallel to *AB*
and

Using ruler and
compasses only, construct a rectangle each of whose diagonals measure 6 cm
and the diagonals interest at an angle of 45^{o}.

To draw the rectangle follows the steps:

(1) Firs
draw a line *AC* of measure 6cm.

(2) Then
draw the perpendicular bisector of *AC*
through *O*.

(3) At
*O* draw an angle of measure . Then produce *OD
*of measure 3cm and *OB *of
measure 3cm each.

(4) Now
join *AD*, *AB*, *BC* and *CD* to form the rectangle.

## Key Features of Study Materials for ICSE Class 9 Maths:

- Include video lessons, question bank and solved sample papers
- Designed according to the latest ICSE syllabus
- Developed by subject experts
- Content revised from time to time
- Helpful when doing quick revision
- Guidance when doing homework
- Understand concepts easily
- Significantly improve your Mathematics score

#### Kindly Sign up for a personalised experience

- Ask Study Doubts
- Sample Papers
- Past Year Papers
- Textbook Solutions

#### Sign Up

#### Verify mobile number

Enter the OTP sent to your number

Change