RD SHARMA Solutions for Class 9 Maths Chapter 12 - Congruent Triangles
Chapter 12 - Congruent Triangles Exercise Ex. 12.1
Chapter 12 - Congruent Triangles Exercise Ex. 12.2
Chapter 12 - Congruent Triangles Exercise Ex. 12.3
Let ABC and DEF be two right triangles.
So, AB = BC = AC
Now, AB = AC
We also have
AC = BC
⇒ ∠B = ∠A (angles opposite to equal sides of a triangle are equal)
So, we have
∠A = ∠B = ∠C
Now, in ΔABC
∠A + ∠B + ∠C = 180o
⇒ ∠A + ∠A + ∠A = 180o
⇒ 3∠A = 180o
⇒ ∠A = 60o
⇒ ∠A = ∠B = ∠C = 60o
Hence, in an equilateral triangle all interior angles are of 60o.
Chapter 12 - Congruent Triangles Exercise Ex. 12.4
Chapter 12 - Congruent Triangles Exercise Ex. 12.5
(i) False
(ii) True
(iii) True
(iv) False
(v) True
(vi) False
(vii) False
(viii) False
(ix) True
(i) equal
(ii) equal
(iii) equal
(iv) BC
(v) AC
(vi) equal to
(vii) EFD
Chapter 12 - Congruent Triangles Exercise Ex. 12.6
Here, 2 + 3 < 7
Hence, it is not possible because triangle can be drawn only if the sum of any two sides is greater than third side.
(i) False
(ii) True
(iii) True
(iv) False
(v) True
(vi) True
(i) largest
(ii) less
(iii) greater
(iv) smaller
(v) less
(vi) greater
Chapter 12 - Congruent Triangles Exercise 12.85
Chapter 12 - Congruent Triangles Exercise 12.86
Chapter 12 - Congruent Triangles Exercise 12.87
Chapter 12 - Congruent Triangles Exercise 12.88
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