RD SHARMA Solutions for Class 10 Maths Chapter 6 - Co-ordinate Geometry
Does the sound of Class 10 Maths intrigue you? Or, does it scare you away? It’s not easy to handle the Board pressure for Class 10. But, we can definitely help you tackle the syllabus for CBSE Class 10 Maths. Scoring more marks in Mathematics CBSE Class 10 has never been this easy before. You just have to start by referring to the CBSE class 10 maths notes.
Our study materials for CBSE Class 10 Mathematics are created by subject experts who teach students Maths. Our materials will help you to score high marks in your Mathematics examination as we focus on providing solutions which simplify the complex fundamentals of a subject. At TopperLearning, we believe in providing quality solutions at a low cost, and we strictly follow the latest CBSE syllabus; our study materials are revised from time to time. Our TopperLearning packages involve all the study resources for CBSE Class 10 such as solved question papers, video lessons and revision notes which will help you to score high marks. We also provide free NCERT and RD Sharma textbook solutions which provide students with step-by-step solutions.
Chapter 6 - Co-ordinate Geometry Exercise 6.63
Question 1
Solution 1
Question 2
Solution 2
Question 3
Solution 3
Question 4
Solution 4
Question 5
Solution 5
Question 6
A line Segement is of length 10 units. If the coordinates of its one end are (2,3) and the abscissa of the other end is 10, then its ordinate is
(a) 9,6
(b) 3,-9
(c) -3,9
(d) 9,-6
Solution 6
Question 7
Solution 7
So, the correct option is (d).
Question 8
Solution 8
Question 9
Solution 9
Question 10
Solution 10
Chapter 6 - Co-ordinate Geometry Exercise 6.64
Question 1
Solution 1
Question 2
If (-1,2),(2,-1) and (3,1) are any three vertices of a parallelogram, then
(a) a = 2, b = 0
(b) a = -2, b = 0
(c) a = -2, b = 6
(d) a = 6, b = 2
Solution 2
Note: The answer does not match the options.
Question 3
If A (5,3), B(11,-5) and P(12,y) are the vertices of a right triangle right angled at P, then y =
(a) - 2,4
(b) -2 ,4
(c) 2, -4
(d) 2,4
Solution 3
Question 4
The area of the triangle formed by (a,b+c), (b,c+a) and (c,a+b) is
(a) a+b+c
(b) abc
(c) (a+b+c)2
(d) 0
Solution 4
Question 5
If (x,2),(-3,-4) and (7,-5) are collinear, then x =
(a) 60
(b) 63
(c) -63
(d) -60
Solution 5
Question 6
Solution 6
Question 7
Solution 7
Question 8
Solution 8
Question 9
Solution 9
Question 10
The line segment joining points (-3,4), and (1,-2) is divided by y - axis in the ratio
(a) 1 : 3
(b) 2 : 3
(c) 3 : 1
(d) 2: 3
Solution 10
Question 11
The ratio in which (4,5) divides the join of (2,3) and (7,8) is
(a) -2 : 3
(b) -3 : 2
(c) 3 : 2
(d) 2 : 3
Solution 11
Question 12
The ratio in which the x-axis divides the segment joining (3,6) and (12,-3) is
(a) 2:1
(b) 1 :2
(c) -2 : 1
(d) 1 : -2
Solution 12
Question 13
If the centrroid of the triangle formed by the points (a,b),(b,c) and (c,a) is at the origin, then a3 + b3 + c3 =
(a) abc
(b) 0
(c) a+b+c
(d) 3abc
Solution 13
Question 14
If points (1, 2), (-5, 6) and (a, -2) are collinear, then a =
(a) -3
(b) 7
(c) 2
(d) -2
Solution 14
Question 15
If the centroid of the triangle formed by (7, x), (y, -6) and (9, 10) is at (6, 3), then (x, y) =
(a) (4, 5)
(b) (5, 4)
(c) (-5, -2)
(d) (5, 2)
Solution 15
Chapter 6 - Co-ordinate Geometry Exercise 6.65
Question 1
The distance of the point (4, 7) from the x-axis is
(a) 4
(b) 7
(c) 11
(d) 
Solution 1
We know, distance of point (x, y) from x-axis is y.
Hence, distance of point (4, 7) from x-axis is 7.
Hence, correct option is (b).
Question 2
The distance of the point (4, 7) from the y-axis is
(a) 4
(b) 7
(c) 11
(d)
Solution 2
We know distance of point (x, y) from y-axis is x.
Hence distance of point (4, 7) from y-axis is 4.
Hence, correct option is (a).
Question 3
If P is a point on x-axis such that its distance from the origin is 3 units, then the coordinates of a point Q on OY such that OP = OQ, are
(a) (0, 3)
(b) (3, 0)
(c) (0, 0)
(d) (0, -3)
Solution 3
Given P is a point on x-axis
Hence P = (x, 0)
Distance from the origin is 3
Hence P = (3, 0)
Given Q is a point on y-axis
So Q is (0, y)
Given that OP = OQ
implies OQ = 3
Distance of Q from the origin is 3
Hence y = 3
implies Q = (0, 3)
Hence, correct option is (a).
Question 4
If the point (x, 4) lies on a circle whose centre is at the origin and radius is 5, then x =
(a) ±5
(b) ±3
(c) 0
(d) ±4
Solution 4
Question 5
If the point P (x, y) is equidistant from A(5, 1) and B (-1, 5), then
(a) 5x = y
(b) x = 5y
(c) 3x = 2y
(d) 2x = 3y
Solution 5
Question 6
If points A (5, p), B (1, 5), C (2, 1) and D (6, 2) form a square ABCD, then p =
(a) 7
(b) 3
(c) 6
(d) 8
Solution 6
Question 7
Solution 7
Question 8
The coordinates of a point on x-axis which lies on the perpendicular bisector of the line segment joining the points (7, 6) and (-3, 4) are
(a) (0, 2)
(b) (3, 0)
(c) (0, 3)
(d) (2, 0)
Solution 8
Question 9
If the centroid of the triangle formed by the points (3, -5), (-7, 4), (10, -k) is at the point (k, - 1), then k =
(a) 3
(b) 1
(c) 2
(d) 4
Solution 9
Question 10
If (-2, 1) is the Centroid of the triangle having its vertices at (x, 2), (10, -2), (-8, y), then x, y satisfy the relation
a. 3x + 8y = 0
b. 3x - 8y = 0
c. 8x + 3y = 0
d. 8x = 3y
Solution 10
The Centroid of the triangle is given by
x=-8 and y=3 satisfy(a) 3x + 8y = 0.
Question 11
The coordinates of the fourth vertex of the rectangle formed by the points (0, 0), (2, 0), (0, 3) are
(a) (3, 0)
(b) (0, 2)
(c) (2, 3)
(d) (3, 2)
Solution 11
Question 12
The length of a line segment joining A(2, -3) and B is 10 units. If the abscissa of B is 10 units, then its ordinates can be
(a) 3 or -9
(b) -3 or 9
(c) 6 or 27
(d) -6 or -27
Solution 12
Question 13
The ratio in which the line segment joining P(x1, y1) and Q(x2, y2) is divided by x-axis is
(a) y1 : y2
(b) -y1 : y2
(c) x1 : x2
(d) -x1 : x2
Solution 13
Question 14
The ratio in which the line segment joining points A(a1, b1) and B(a2, b2) is divided by y-axis is
(a) -a1 : a2
(b) a1 : a2
(c) b1 : b2
(d) -b1 : b2
Solution 14
Chapter 6 - Co-ordinate Geometry Exercise 6.66
Question 1
Solution 1
Question 2
If the coordinates of one end of a diameter of a circle are (2, 3) and the coordinates of its centre are (-2, 5), then the coordinates of the other end of the diameter are
(a) (-6, 7)
(b) (6, -7)
(c) (6, 7)
(d) -6, -7)
Solution 2
Question 3
The coordinates of the point P dividing the line segment joining the points A (1, 3) and B (4, 6) in the ratio 2 : 1 are
(a) (2, 4)
(b) (3, 5)
(c) (4, 2)
(d) (5, 3)
Solution 3
Question 4
In the figure, the area of ΔABC (in square units) is
(a) 15
(b) 10
(c) 7.5
(d) 2.5
Solution 4
Question 5
The point on the x-axis which is equidistant from points (-1, 0) and (5, 0) is
(a) (0, 2)
(b) (2, 0)
(c) (3, 0)
(d) (0, 3)
Solution 5
Question 6
Solution 6
Question 7
If P(2, 4), Q(0,3), R (3, 6) and S (5, y) are the vertices of a parallelogram PQRS, then the value of y is
(a) 7
(b) 5
(c) -7
(d) -8
Solution 7
Question 8
If A(x, 2), B (-3, -4) and C (7, -5) are collinear, then the value of x is
(a) -63
(b) 63
(c) 60
(d) -60
Solution 8
Question 9
Solution 9
Chapter 6 - Co-ordinate Geometry Exercise 6.67
Question 1
If the point P(2, 1) lies on the line segment joining points A (4, 2) and B (8, 4), then
Solution 1
Question 2
A line intersects the y-axis and x-axis at P and Q, respectively, If (2, -5) is the mid-point of PQ, then the coordinates of P and Q are respectively
a. (0, -5) and (2, 0)
b. (0, 10) and (-4, 0)
c. (0, 4) and (-10, 0)
d. (0, -10) and (4, 0)
Solution 2
Chapter 6 - Co-ordinate Geometry Exercise Ex. 6.1
Question 1
Solution 1
Question 2
Solution 2
Question 3
Solution 3
Chapter 6 - Co-ordinate Geometry Exercise Ex. 6.2
Question 1
Show that ∆ABC, where A (-2, 0), B (2, 0) C (0, 2) and ∆PQR, where P (-4, 0), Q (4, 0), R (0, 4) are similar.
Solution 1
Using the distance formula,
AB=
AC=
BC=
PQ=
PR=
QR=
Now,
ΔABC ~ ΔPQR
by the SSS test.
Question 2
Solution 2
Question 3
Solution 3
Question 4
Solution 4
Question 5
Solution 5
Question 6
Solution 6
Question 7
Solution 7
Question 8
Solution 8
Question 9
Solution 9
Question 10
Solution 10
Question 11
Show that the points A(1,-2), B(3,6), C(5,10) and D(3,2) are the vertices of a parallelogram.
Solution 11
Question 12
Prove that the points (1, 7), (4, 2), (-1, -1) and (-4, 4) are the vertices of a square.
Solution 12
Question 13
Solution 13
Question 14
Solution 14
Question 15
Solution 15
Question 16
Solution 16
Question 17
The points A(2, 9), B(a, 5) and C(5, 5) are the vertices of triangle ABC right angled at B. Find the values of a and hence the area of ⧍ABC.
Solution 17
Question 18
Solution 18
Question 19
Solution 19
Question 20
Solution 20
Question 21
Solution 21
Question 22
Solution 22
Question 23
Solution 23
Question 24
Solution 24
Question 25
Find a point which is equidistant from the points
A (-5, 4) and B (-1, 6). How many such points are there?
Solution 25
Question 26
The centre of a circle is (2a, a - 7). Find the values of a if the circle passes through the point (11, -9) and has diameter 
units.
Solution 26
Question 27
Ayush starts walking from his house to office, Instead of going to the office directly, he goes to bank first, from there to his daughter's school and then reaches the office. What is the extra distance travelled by Ayush in reaching the office? (Assume that all distance covered are in straight lines). If the house is situated at (2, 4), bank at (5, 8) school at (13, 14) and office at (13, 26) and coordinates are in kilometer.
Solution 27
Question 28
Solution 28
Question 29
If (-4, 3) and (4, 3) are two vertices of an equilateral triangle, find the coordinates of the third vertex, given that the origin lies in the (i) interior (ii) exterior of the triangle.
Solution 29
Question 30
Solution 30
Question 31
Solution 31
Question 32
Solution 32
Question 33
Show that the points A(5,6), B(1,5), C(2,1) and D(6,2) are the vertices of a square.
Solution 33
Question 34
Prove that the points A(2, 3), B(-2, 2), C(-1, -2), and D (3, -1) are the vertices of a square ABCD.
Solution 34
Question 35
Solution 35
Question 36
Solution 36
Question 37
Solution 37
Question 38
Solution 38
Question 39
If the point P(x,y) is equidistant from the points A(5,1) and B(1,5), prove that x = y.
Solution 39
Question 40
Solution 40
Question 41
Solution 41
Question 42
If the point P(k-1, 2) is equidistant from the points A(3, k) and B(k, 5), find the values of k.
Solution 42
Question 43
If the point A(0, 2) is equidistant from the points B(3, p) and C(p, 5), find p. Also, find the length of AB.
Solution 43
Question 44
Solution 44
Question 45
Find the equation of the perpendicular bisector of the line segment joining points (7,1) and (3,5).
Solution 45
Question 46
Prove that the points (3,0), (4,5), (-1,4) and (-2,-1), taken in order, form a rhombus. Also, find its area.
Solution 46
Question 47
Solution 47
Question 48
Solution 48
Question 49
Solution 49
Question 50
If a point A(0,2) is equidistant from the points B(3,p) and C(p,5), then find the value of p.
Solution 50
Question 51
Prove that the points (7, 10), (-2, 5) and (3, -4) are the vertices of an isosceles right triangle.
Solution 51
Question 52
If the point P(x, 3) is equidistant from the points A(7, -1) and B(6, 8), find the value of x and the find the distance AP.
Solution 52
Question 53
If A(3, y) is equidistant from the points P(8, - 3) and Q(7, 6), find the value of y and find the distance AQ.
Solution 53
Question 54
If (0, -3) and (0, 3) are the two vertices of an equilateral triangle, find the coordinates of its third vertex.
Solution 54
For an equilateral triangle, the perpendicular bisector of any side passes through the opposite vertex.
Both the points, (0, -3) and (0, 3), lie on the y-axis equidistant from the origin. Hence, the perpendicular bisector joining these two points is the x-axis.
Any point on the x-axis has the coordinates (a, 0).
The distance between (0, -3) and (0, 3) is 6.
Hence, the distance between (a, 0) and (0, 3) should also be 6.
62 = (a - 0)2 + (0 - 3)2
36 = a2 + 9
a2 = 27
Question 55
If the point P(2, 2) is equidistant from the points A(-2, k) and B(-2k, -3), find k. Also, find the length of AP.
Solution 55
Question 56
Solution 56
Question 57
Find the circumcentre of the triangle whose vertices are (-2,-3), (-1,0), (7,-6).
Solution 57
Question 58
Solution 58
Question 59
Find the centre of the circle passing through (5, -8), (2, -9) and (2, 1).
Solution 59
Question 60
Solution 60
Question 61
Solution 61
Question 62
Solution 62
Chapter 6 - Co-ordinate Geometry Exercise Ex. 6.3
Question 1
Solution 1
Question 2
Find the points of trisection of the line segment joining the points:
(i) (5, -6) and (-7, 5), (ii) (3, -2) and (-3,-4), (iii) (2,-2) and (-7,4).
Solution 2
(i) 
(ii) 
(iii) 
Question 3
Solution 3
Question 4
Solution 4
Question 5
If P(9a - 2, -b) divides the line segment joining A(3a + 1, -3) and B(8a, 5) in the ratio 3 : 1, find the values of a and b.
Solution 5
Question 6
If (a, b) is the mid-point of the line segment joining the points A (10, -6), B(k, 4) and a - 2b = 18, find the value of k and the distance AB.
Solution 6
Question 7
Solution 7
Question 8
Solution 8
Question 9
If the points P,Q(x, 7), R, S(6, y) in this order divide the line segment joining A(2, p) and B (7, 10) in 5 equal parts, find x, y and p.
Solution 9
Question 10
Solution 10
Question 11
Solution 11
Question 12
Solution 12
Question 13
Solution 13
Question 14
Solution 14
Question 15
Solution 15
*Note: (i) Answer given in the book is incorrect.
Question 16
Solution 16
Question 17
Prove that (4,3), (6,4), (5,6) and (3,5) are the angular points of a square.
Solution 17
Question 18
Solution 18
Question 19
Solution 19
Question 20
Find the ratio in which the line segment joining the points A (3, -3) and B (-2, 7) is divided by x- axis. Also, find the coordinates of the point of division.
Solution 20
Let the point on the x-axis be (a, 0).
Let this point divide the line segment AB in the ratio of r : 1.
Using the section formula for the y-coordinate, we get
Question 21
Find the ratio in which the point P(x, 2) divides the line segment joining the points A (12, 5) and B (4, -3). Also, find the value of x.
Solution 21
Question 22
Find the ratio in which the point P(-1, y) lying on the line segment joining A(-3, 10) and B(6, -8) divides it. Also find the value of y.
Solution 22
Question 23
Solution 23
Question 24
Solution 24
Question 25
Solution 25
Question 26
In what ratio does the point (-4,6) divide the line segment joining the points A(-6,10) and B(3,-8)?
Solution 26
Question 27
Solution 27
Question 28
Solution 28
Question 29
Solution 29
Question 30
Solution 30
Question 31
Solution 31
Question 32
Solution 32
Question 33
Solution 33
Question 34
Solution 34
Question 35
Show that the points A(1,0) B(5,3), C(2,7) and D(-2,4) are the vertices of a parallelogram.
Solution 35
Question 36
Solution 36
Question 37
Solution 37
Question 38
Solution 38
Question 39
Points P, Q, R and S divide the line segment joining the points A(1, 2) and B(6, 7) in 5 equal parts. Find the coordinates of the points P, Q, and R.
Solution 39
The difference between the x-coordinates of A and B is 6 - 1 = 5
Similarly, the difference between the y-coordinates of A and B is 7 - 2 = 5
Hence, if the line segment joining A(1, 2) and B(6, 7) is divided into 5 equal parts by the points P, Q, R and S, then the coordinates of P, Q, R and S can be found out by increasing the x and the y coordinates of A by 1 successively.
Hence, the coordinates of P are (1 + 1, 2 + 1) = (2, 3)
The coordinates of Q are (2 + 1, 3 + 1) = (3, 4)
The coordinates of R are (3 + 1, 4 + 1) = (4, 5)
Question 40
Solution 40
Question 41
Solution 41
Question 42
Solution 42
Question 43
Solution 43
Question 44
Solution 44
Question 45
Solution 45
Question 46
Solution 46
Question 47
If two vertices of a parallelogram are (3,2), (-1,0) and the diagonals cut at (2,-5), find the other vertices of the parallelogram.
Solution 47
Question 48
If the coordinates of the mid-points of the sides of a triangle are (3,4), (4,6), and (5,7), find its vertices.
Solution 48
Question 49
Solution 49
Question 50
Solution 50
Question 51
Solution 51
Question 52
Solution 52
Question 53
Solution 53
Question 54
Solution 54
Question 55
Solution 55
Question 56
Solution 56
Question 57
A point P divides the line segment joining the points A(3,-5) and B(-4,8), such that 
. If P lies on the line x + y = 0, then find the value of k.
Solution 57
Given points are A(3,-5) and B(-4,8).
P divides AB in the ratio k : 1.
Using the section formula, we have:
Coordinate of point P are {(-4k+3/k+1)(8k-5/k+1)}
Now it is given, that P lies on the line x+y = 0
Therefore,
-4k+3/k+1 + 8k-5/k+1 =0
=> -4k+3+8k-5 =0
=> 4k -2 =0
=> k=2/4
=> k=1/2
Thus, the value of k is 1/2.
Question 58
The mid - point P of the line segment joining the points A (-10, 4) and B (-2, 0) lies on the line segment joining the points C (-9, -4) and D (-4, y). Find the ratio in which P divides CD. Also, find the value of y.
Solution 58
Question 59
If the point C(-1, 2) divides internally the line segment joining the points A(2, 5) and B(x, y) in the ratio 3 : 4, find the value of x2 + y2.
Solution 59
Question 60
ABCD is a parallelogram with vertices A(x1, y1), B(x2, y2) and C (x3, y3). Find the coordinates of the fourth vertex D in terms of x1, x2, x3, y1, y2 and y3.
Solution 60
Question 61
The points A (x1, y1), B(x2, y2) and C (x3, y3) are the vertices of ⧍ABC.
i. The median from A meets BC at D. Find the coordinates of the point D.
ii. Find the coordinates of the point P on AD such that AP : PD = 2 : 1.
iii. Find the points of coordinates Q and R on medians BE and CF respectively such that BQ : QE = 2 : 1 and CR : RF = 2 : 1.
iv. What are the coordinates of the centroid of the triangle ABC
Solution 61
Chapter 6 - Co-ordinate Geometry Exercise Ex. 6.4
Question 1
Solution 1
Question 2
Solution 2
Question 3
Solution 3
Question 4
Solution 4
Question 5
Solution 5
Question 6
Solution 6
Question 7
Prove analytically that the line segment joining the middle points of two sides of a triangle is equal to half of the third side.
Solution 7
Question 8
Solution 8
Question 9
Solution 9
Question 10
Solution 10
Question 11
Solution 11
Chapter 6 - Co-ordinate Geometry Exercise Ex. 6.5
Question 1
Solution 1
Question 2
Solution 2
Question 3
Solution 3
Question 4
Find the area of the quadrilaterals, the coordinates of whose vertices are
(-4,-2), (-3,-5), (3,-2), (2,3)
Solution 4
Question 5
Solution 5
Question 6
Solution 6
Question 7
Solution 7
Question 8
Find the area of a quadrilateral ABCD, the coordinates of whose vertices are A(-3, 2), B(5, 4), C(7, -6) and D(-5, -4).
Solution 8
Question 9
In ⧍ABC, the coordinates of vertex A are (0, -1) and D(1, 0) and E(0, 1) respectively the mid-points of the sides AB and AC. If F is the mid-point of side BC, find the area of ⧍DEF.
Solution 9
Question 10
Find the area of the triangle PQR with Q (3, 2) and the mid-points of the sides through Q being (2, -1) and (1, 2).
Solution 10
Question 11
If P(-5, -3), Q(-4, -6), R(2, -3) and S(1, 2) are the vertices of a quadrilateral PQRS, find its area.
Solution 11
Question 12
If A (-3, 5), B(-2, -7), C(1, -8) and D(6, 3) are the vertices of a quadrilateral ABCD, find its area.
Solution 12
Question 13
Solution 13
Question 14
Solution 14
Question 15
If the vertices of a triangle are (1,-3), (4,p) and (-9, 7) and its area is 15 sq. units, find the value (s) of p.
Solution 15
Question 16
Solution 16
Question 17
Solution 17
Question 18
Solution 18
Question 19
Solution 19
Question 20
Solution 20
Question 21
Solution 21
Question 22
Find the value of a for which the area of the triangle formed by the points A(a, 2a), B(-2, 6) and C (3, 1) is 10 sequare units.
Solution 22
Question 23
If a ≠ b ≠ 0, prove that the points (a, a2), (b, b2), (0, 0) are never collinear.
Solution 23
Let the points (a, a2), (b, b2), (0, 0) represent a triangle. If we can prove that the area of the triangle so formed is not equal to zero, then we can prove that the points (a, a2), (b, b2), (0, 0) are never collinear.
Area of a triangle is given by
Now b≠a≠0.
So,
b - a≠0,
Δ≠0
Thus, points (a, a2), (b, b2), (0, 0) are never collinear.
Question 24
The area of a triangle is 5 sq. units. Two of its vertices are at (2, 1) and (3, -2). If the third vertex is (7/2, y), find y.
Solution 24
Area
of a triangle is given by
Question 25
Solution 25
Question 26
Solution 26
Question 27
Solution 27
Question 28
Solution 28
Question 29
Solution 29
Question 30
Solution 30
Question 31
Solution 31
Question 32
Find the value (s) of k for which the points (3k - 1, k - 2), (k, k - 7) and (k - 1, -k - 2) are collinear.
Solution 32
Let the points be A, B and C respectively.
If A, B and C are collinear, then the area of ∆ABC is zero.
Question 33
If the points A(-1, -4), B(b, c) and C(5, -1) are collinear and 2b + c = 4, find the values of b and c.
Solution 33
Question 34
If the points A(-2, 1), B(a, b) and C(4, -1) are collinear and a - b = 1, find the values of a and b.
Solution 34
Question 35
If the points A(1, -2), B(2, 3), C(a, 2) and D(-4, -3) form a parallelogram, find the value of a and height of the parallelogram taking AB as base.
Solution 35
Question 36
A(6, 1), B(8, 2) and C(9, 4) are three vertices of a parallelogram ABCD. If E is the mid-point of DC, find the area of ⧍ADE.
Solution 36
Question 37
If D(-1/5, 5/2), E(7, 3) and F(7/2, 7/2) are the mid-points of sides of ⧍ABC, find the area of ⧍ABC
Solution 37
Why to choose our CBSE Class 10 Maths Study Materials?
- Contain 950+ video lessons, 200+ revision notes, 8500+ questions and 15+ sample papers
- Based on the latest CBSE syllabus
- Free textbook solutions & doubt-solving sessions
- Ideal for quick revision
- Help score more marks in the examination
- Increase paper-solving speed and confidence with weekly tests
Kindly Sign up for a personalised experience
- Ask Study Doubts
- Sample Papers
- Past Year Papers
- Textbook Solutions
Sign Up
Verify mobile number
Enter the OTP sent to your number
Change