NCERT Solutions for Class 10 Maths Chapter 7 - Coordinate Geometry
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Chapter 7 - Coordinate Geometry Exercise Ex. 7.1
In section 7.2, A is (4,0) and B is (6,0).
AB2 = (6 - 4)2 - (0 - 0)2 = 4
AB = 2
Three non collinear points will represent the vertices of an isosceles triangle, if its two sides are of equal length.
From the figure coordinates of points A, B, C and D are
A = (3, 4), B = (6, 7), C = (9, 4), D = (6, 1)
Here all sides of this quadrilateral are of different length. So, we can say that it is only a general quadrilateral not specific like square, rectangle etc.
(iii) Let A = (4, 5), B = (7, 6), C = (4, 3), D = (1, 2)
Here opposite sides of this quadrilateral are of same length but diagonals are of different length. So, given points are vertices of a parallelogram.
Concept Insight: Recall the properties of various quadrilaterals.
Chapter 7 - Coordinate Geometry Exercise Ex. 7.2
If the ratio in which P divides AB is k:1 , then the co-ordinates of the point P will be
Use the property of a parallelogram that the diagonals of a Parallelogram bisects each other for finding the values of a and y.
Chapter 7 - Coordinate Geometry Exercise Ex. 7.3
Let vertices of the triangle be A (0, –1), B (2, 1), C (0, 3)
Let D, E, F are midpoints of the sides of this triangle. Coordinates of D, E, and F are given by –
Chapter 7 - Coordinate Geometry Exercise Ex. 7.4
So, D and E are two points on side AB and AC respectively such that they divide side AB and AC in the ratio 1:3
Coordinates of the point P(x,y) which divides the line segment joining the points points A(x1,y1) and B(x2,y2) internally in the ratio m1:m2 are
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