NCERT Solutions for Class 10 Maths Chapter 7 - Coordinate Geometry
Refer to TopperLearning’s NCERT Solutions for CBSE Class 10 Mathematics Chapter 7 Coordinate Geometry to score top marks in the exam. Learn to use the given information on the vertices and diagonals of a figure to answer questions on the figure. Go through the solutions to understand how to find the distance between two points as per the given data.
Get the best CBSE Class 10 study resources to master Maths concepts such as properties of a parallelogram, properties of a rhombus etc. For complete revision of the Mathematics syllabus, you can brush up on concepts using our sample papers, past years’ question papers and other resources.
Chapter 7 - Coordinate Geometry Exercise Ex. 7.1
Solution 1
Solution 2
In section 7.2, A is (4,0) and B is (6,0).
AB2 = (6 - 4)2 - (0 - 0)2 = 4
AB = 2
Solution 3
Solution 4
Three non collinear points will represent the vertices of an isosceles triangle, if its two sides are of equal length.
Solution 5
From the figure coordinates of points A, B, C and D are
A = (3, 4), B = (6, 7), C = (9, 4), D = (6, 1)
Solution 6
Here all sides of this quadrilateral are of different length. So, we can say that it is only a general quadrilateral not specific like square, rectangle etc.
(iii) Let A = (4, 5), B = (7, 6), C = (4, 3), D = (1, 2)
Here opposite sides of this quadrilateral are of same length but diagonals are of different length. So, given points are vertices of a parallelogram.
Concept Insight: Recall the properties of various quadrilaterals.
Solution 7
Solution 8
Solution 9
Solution 10
Chapter 7 - Coordinate Geometry Exercise Ex. 7.2
Solution 1
Solution 2
Solution 3
Solution 4
Solution 5
If the ratio in which P divides AB is k:1 , then the co-ordinates of the point P will be
Solution 6
Concept Insight:
Use the property of a parallelogram that the diagonals of a Parallelogram bisects each other for finding the values of a and y.
Solution 7
Solution 8
Solution 9
Solution 10
Chapter 7 - Coordinate Geometry Exercise Ex. 7.3
Solution 1
Solution 2
Solution 3
Let vertices of the triangle be A (0, –1), B (2, 1), C (0, 3)
Let D, E, F are midpoints of the sides of this triangle. Coordinates of D, E, and F are given by –
Solution 4
Solution 5
Chapter 7 - Coordinate Geometry Exercise Ex. 7.4
Solution 1
Solution 2
Solution 3
Solution 4
Solution 5
Solution 6
So, D and E are two points on side AB and AC respectively such that they divide side AB and AC in the ratio 1:3
Coordinates of the point P(x,y) which divides the line segment joining the points points A(x1,y1) and B(x2,y2) internally in the ratio m1:m2 are
Solution 7
Note:
Coordinates of the point P(x,y) which divides the line segment joining the points points A(x1,y1) and B(x2,y2) internally in the ratio m1:m2 are
Solution 8
Other Chapters for CBSE Class 10 Mathematics
Chapter 1- Real Numbers Chapter 2- Polynomials Chapter 3- Pairs of Linear Equations in Two Variables Chapter 4- Quadratic Equations Chapter 5- Arithmetic Progressions Chapter 6- Triangles Chapter 8- Introduction to Trigonometry Chapter 9- Some Applications of Trigonometry Chapter 10- Circles Chapter 11- Constructions Chapter 12- Areas Related to Circles Chapter 13- Surface Areas and Volumes Chapter 14- Statistics Chapter 15- ProbabilityNCERT Solutions for CBSE Class 10 Subjects
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