Archive
28th of March 2017
Mathematics
Q:

in a circle with center O QR is a diameter and a tangent AB touches the circle at P QP and QR are joined angle PQR is 30 degree find angle APQ. please answer tomorrow is my maths exam

Sanyagandhi05 - Junior - Class I

Tuesday, March 28, 2017 at 18:16:PM

A:

begin mathsize 16px style To space find colon space angle APQ
Since space QR space is space the space diameter comma space QPR space equals 90 degree space left parenthesis Since space angle space in space straight a space substended space by space the space diameter space in space straight a space semicircle space is space 90 degree right parenthesis
Using space alternate space segment space theorem comma
angle RPB equals angle PQR equals 30 degree
So comma space angle APQ plus angle QPR plus angle RPB equals 180 degree
rightwards double arrow angle APQ plus 90 degree plus 30 degree equals 180 degree
rightwards double arrow angle APQ equals 60 degree
end style

Hi, 

We would also like to wish you All the best for your exam tomorrow. Smile

Tuesday, March 28, 2017 at 19:11:PM