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I f space tan theta plus s e c theta equals l comma space t h e n space p r o v e space t h a t space s e c theta equals l squared plus l divided by 2 l
Asked by archita123 | 07 Sep, 2015, 03:52: PM
answered-by-expert Expert Answer

G i v e n space t h a t space tan theta plus s e c theta equals l rightwards double arrow fraction numerator sin theta over denominator cos theta end fraction plus fraction numerator 1 over denominator cos theta end fraction equals l rightwards double arrow fraction numerator 1 plus sin theta over denominator cos theta end fraction equals l rightwards double arrow fraction numerator 1 plus s i n theta over denominator c o s theta end fraction cross times fraction numerator 1 minus sin theta over denominator 1 minus sin theta end fraction equals l rightwards double arrow fraction numerator 1 minus s i n squared theta over denominator c o s theta open parentheses 1 minus s i n theta close parentheses end fraction equals l rightwards double arrow fraction numerator cos squared theta over denominator c o s theta open parentheses 1 minus s i n theta close parentheses end fraction equals l rightwards double arrow fraction numerator c o s theta over denominator open parentheses 1 minus s i n theta close parentheses end fraction equals l rightwards double arrow fraction numerator 1 minus s i n theta over denominator c o s theta end fraction equals 1 over l rightwards double arrow fraction numerator 1 over denominator c o s theta end fraction minus fraction numerator s i n theta over denominator c o s theta end fraction equals 1 over l rightwards double arrow s e c theta minus fraction numerator s i n theta over denominator c o s theta end fraction equals 1 over l rightwards double arrow s e c theta minus tan theta equals 1 over l rightwards double arrow s e c theta minus open parentheses l minus s e c theta close parentheses equals 1 over l space space space space space space open square brackets because t a n theta plus s e c theta equals l rightwards double arrow t a n theta equals l minus s e c theta close square brackets rightwards double arrow s e c theta minus l plus s e c theta equals 1 over l rightwards double arrow 2 s e c theta equals 1 over l plus l rightwards double arrow 2 s e c theta equals fraction numerator 1 plus l squared over denominator l end fraction rightwards double arrow s e c theta equals fraction numerator 1 plus l squared over denominator 2 l end fraction

Answered by | 07 Sep, 2015, 06:37: PM

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