Class 9 FRANK Solutions Maths Chapter 15 - Mid-point and Intercept Theorems
Practise Frank Solutions for ICSE Class 9 Mathematics Chapter 15 Mid-point and intercept theorems at TopperLearning. If you find questions on working with the mid-point of sides of a triangle mind-boggling, our reference solutions will help you. Whether it is sides of a rhombus or a parallelogram, you can check the steps that experts will use to solve Maths problems.
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Mid-point and Intercept Theorems Exercise Ex. 15.1
Solution 3(a)
Solution 3(b)
Solution 3(c)
Solution 5
Solution 11
Solution 15(a)
Let us draw a diagonal AC which meets PQ at O as shown below:
Solution 18
Construction: Draw DS ∥ BF, meeting AC at S.
Solution 24
Solution 1
Solution 2
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Solution 7
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Solution 12
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Solution 23
Mid-point and Intercept Theorems Exercise Ex. 15.2
Solution 1
Solution 2
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Solution 5
The figure is as below:
Let ABCD be a quadrilateral where P, Q, R, S are the midpoints of sides AB, BC, CD, DA respectively.
Diagonals AC and BD intersect at right angles at point O. We need to show that PQRS is a rectangle
Solution 6
Note: This question is incomplete.
According to the information given in the question,
F could be any point on BC as shown below:
So, this makes it impossible to prove that DP = DE, since P too would shift as F shift because P too would be any point on DE as F is.
Note: If we are given F to be the mid-point of BC, the result can be proved.
Solution 7
From the figure EF ∥ AB and E is the midpoint of BC.
Therefore, F is the midpoint of AC.
Here EF ∥ BD, EF = BD as D is the midpoint of AB.
BE ∥ DF, BE = DF as E is the midpoint of BC.
Therefore BEFD is a parallelogram.
Remark: Figure modified
Solution 8
Solution 9
