Class 10 FRANK Solutions Maths Chapter 8: Reflection
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Ex. 8.1
Reflection Exercise Ex. 8.1
Solution 1
(i) (3,-9)
The co-ordinate of the given point under reflection in the x-axis is: (3,9).
(ii) (-7, 5)
The co-ordinate of the given point under reflection in the x-axis is: (-7,-5).
(iii) (0, 6)
The co-ordinate of the given point under reflection in the x-axis is: (0,-6).
(iv) (-4,-8)
The co-ordinate of the given point under reflection in the x-axis is: (-4, 8).
The co-ordinate of the given point under reflection in the x-axis is: (3,9).
(ii) (-7, 5)
The co-ordinate of the given point under reflection in the x-axis is: (-7,-5).
(iii) (0, 6)
The co-ordinate of the given point under reflection in the x-axis is: (0,-6).
(iv) (-4,-8)
The co-ordinate of the given point under reflection in the x-axis is: (-4, 8).
Solution 2
(i) (2, 8)
The co-ordinate of the given point under reflection in the y-axis is: (-2,8).
(ii) (-1,-3)
The co-ordinate of the given point under reflection in the y-axis is: (1,-3).
(iii) (5,-6)
The co-ordinate of the given point under reflection in the y-axis is: (-5,-6).
(iv) (-4, 7)
The co-ordinate of the given point under reflection in the y-axis is: (4, 7).
The co-ordinate of the given point under reflection in the y-axis is: (-2,8).
(ii) (-1,-3)
The co-ordinate of the given point under reflection in the y-axis is: (1,-3).
(iii) (5,-6)
The co-ordinate of the given point under reflection in the y-axis is: (-5,-6).
(iv) (-4, 7)
The co-ordinate of the given point under reflection in the y-axis is: (4, 7).
Solution 3
(i) (-1,-4)
The co-ordinate of the given point under reflection in the origin is: (1, 4)
(ii) (2, 7)
The co-ordinate of the given point under reflection in the origin is: (-2,-7)
(iii) (0, 2)
The co-ordinate of the given point under reflection in the origin is: (0,-2)
(iv) (9,-9)
The co-ordinate of the given point under reflection in the origin is: (-9, 9)
The co-ordinate of the given point under reflection in the origin is: (1, 4)
(ii) (2, 7)
The co-ordinate of the given point under reflection in the origin is: (-2,-7)
(iii) (0, 2)
The co-ordinate of the given point under reflection in the origin is: (0,-2)
(iv) (9,-9)
The co-ordinate of the given point under reflection in the origin is: (-9, 9)
Solution 4
P' = (2, 10). Therefore, the co-ordinates of P under reflection in the x-axis = (2,-10)
Solution 5
S= (2,-5). Therefore, the co-ordinates of S' under reflection in the origin = (-2, 5)
Solution 6
P' = (-3, 4).
Therefore, the co-ordinates of P under reflection in the x-axis = (-3,-4)
and the co-ordinates of P" under reflection in the origin = (3,-4).
The single transformation = reflection in the y-axis.
Therefore, the co-ordinates of P under reflection in the x-axis = (-3,-4)
and the co-ordinates of P" under reflection in the origin = (3,-4).
The single transformation = reflection in the y-axis.
Solution 7
P' = (8,-6).
Therefore, the co-ordinates of P under reflection in the x-axis = (8, 6)
and the co-ordinates of P" under reflection in the y-axis = (-8, 6).
Therefore, the co-ordinates of P under reflection in the x-axis = (8, 6)
and the co-ordinates of P" under reflection in the y-axis = (-8, 6).
Solution 8
Solution 9
B = (3, 2), Therefore, reflection of B in the x-axis is B'= (3,-2)
C = (0, 3), Therefore, reflection of C in the line B is C' = (6, 3).
C = (0, 3), Therefore, reflection of C in the line B is C' = (6, 3).
Solution 10
P"= (5,-2), therefore, co-ordinates of P' = (-5, 2) and hence the coordinates of P = (-5,-2)
Single transformation = reflection in the y-axis
Single transformation = reflection in the y-axis
Solution 11
Solution 12
Solution 13
P = (-8, 1), therefore co-ordinates of P' under reflection in the x-axis = (-8, -1).
Hence, the co-ordinates of P" under reflection in the origin = (8, 1).
The single transformation = reflection in the y-axis.
Hence, the co-ordinates of P" under reflection in the origin = (8, 1).
The single transformation = reflection in the y-axis.
Solution 14
Solution 15
(i) y = 0
Co-ordinates of image = (-5, 2x0-4)= (-5,-4)
(ii) y = 4
Co-ordinates of image = (-5, 2x4-4)= (-5,4)
Co-ordinates of image = (-5, 2x0-4)= (-5,-4)
(ii) y = 4
Co-ordinates of image = (-5, 2x4-4)= (-5,4)
Solution 16
(i) x = 0
Co-ordinates of image =(2x0-4,-1)= (-4,-1)
(ii) y = 5
Co-ordinates of image = (4, 2x5-(-1)) = (4, 11)
Co-ordinates of image =(2x0-4,-1)= (-4,-1)
(ii) y = 5
Co-ordinates of image = (4, 2x5-(-1)) = (4, 11)
Solution 17
Solution 18
Solution 19
