# Chapter 8 : Reflection - Frank Solutions for Class 10 Maths ICSE

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## Chapter 8 - Reflection Exercise Ex. 8.1

(i) (3,-9)

(ii) (-7, 5)

(iii) (0, 6)

(iv) (-4,-8)

The co-ordinate of the given point under reflection in the x-axis is: (3,9).

(ii) (-7, 5)

The co-ordinate of the given point under reflection in the x-axis is: (-7,-5).

(iii) (0, 6)

The co-ordinate of the given point under reflection in the x-axis is: (0,-6).

(iv) (-4,-8)

The co-ordinate of the given point under reflection in the x-axis is: (-4, 8).

(i) (2, 8)

(ii) (-1,-3)

(iii) (5,-6)

(iv) (-4, 7)

The co-ordinate of the given point under reflection in the y-axis is: (-2,8).

(ii) (-1,-3)

The co-ordinate of the given point under reflection in the y-axis is: (1,-3).

(iii) (5,-6)

The co-ordinate of the given point under reflection in the y-axis is: (-5,-6).

(iv) (-4, 7)

The co-ordinate of the given point under reflection in the y-axis is: (4, 7).

(i) (-1,-4)

(ii) (2, 7)

(iii) (0, 2)

(iv) (9,-9)

The co-ordinate of the given point under reflection in the origin is: (1, 4)

(ii) (2, 7)

The co-ordinate of the given point under reflection in the origin is: (-2,-7)

(iii) (0, 2)

The co-ordinate of the given point under reflection in the origin is: (0,-2)

(iv) (9,-9)

The co-ordinate of the given point under reflection in the origin is: (-9, 9)

Therefore, the co-ordinates of P under reflection in the x-axis = (-3,-4)

and the co-ordinates of P" under reflection in the origin = (3,-4).

The single transformation = reflection in the y-axis.

Therefore, the co-ordinates of P under reflection in the x-axis = (8, 6)

and the co-ordinates of P" under reflection in the y-axis = (-8, 6).

C = (0, 3), Therefore, reflection of C in the line B is C' = (6, 3).

P" are (5,-2), write down the co-ordinates of P. State the single transformation that takes place.

Single transformation = reflection in the y-axis

Hence, the co-ordinates of P" under reflection in the origin = (8, 1).

The single transformation = reflection in the y-axis.

(i) y = 0

(ii) y = 4

Co-ordinates of image = (-5, 2x0-4)= (-5,-4)

(ii) y = 4

Co-ordinates of image = (-5, 2x4-4)= (-5,4)

(i) x = 0

(ii) y = 5

Co-ordinates of image =(2x0-4,-1)= (-4,-1)

(ii) y = 5

Co-ordinates of image = (4, 2x5-(-1)) = (4, 11)

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