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Quadratic Equations

Quadratic Equations Synopsis

Synopsis

 

  • An equation of the form ax2+bx +c = 0 is called a quadratic equation, where a, b, c are real numbers and a ≠ 0.

Roots of the quadratic equation 

  • The value of x that satisfies an equation is called the roots of the equation. 
  • A real number a is said to be a solution/root of the quadratic equation ax2 + bx + c = 0 if aa2 + ba + c = 0.
  • A quadratic equation has at most two roots

Solving Quadratic Equation by:

  1. Splitting the middle term (or factorization) method
    If ax2 + bx + c = 0, a ≠ 0, can be reduced to the product of two linear factors, then the roots of the quadratic equation ax2 + bx + c = 0 can be found by equating each factor to zero.
    Steps involved in solving quadratic equationax2 +bx+c = 0(a ≠0) by splitting the middle term (or factorization) method:
    Step 1: Find the product ac.
    Step 2: Find the factors of ‘ac’ that add up to b, using the following criteria:
    i.If ac > 0 and b > 0, then both the factors are positive.
    ii.If ac > 0 and b < 0, then both the factors are negative.
    iii.If ac < 0 and b > 0, then larger factor is positive and smaller factor is negative.
    iv.If ac < 0 and b < 0, then larger factor is negative and smaller factor is positive.
    Step 3: Split the middle term into two parts using the factors obtained in the above step.
    Step 4: Factorize the quadratic equation obtained in the above step by grouping method. Two factors will be obtained.
    Step 5: Equate each of the linear factors to zero to get the value of x.

  2. Completing the square method
    Any quadratic equation can be converted to the form (x + a)2 – b2 = 0 or (x – a)2 + b2 = 0 by adding and subtracting the constant term. This method of finding the roots of quadratic equation is called the method of completing the square.
    The steps involved in solving a quadratic equation by completing the square, are as follows:
    Step 1: Make the coefficient of x2 unity.
    Step 2: Express the coefficient of x in the form 2⨯ x ⨯  p.
    Step 3: Add and subtract the square of p.
    Step 4: Use the square identity (a + b)2 or (a – b)2 to obtain the quadratic equation in the required form (x + a)2 - b2 = 0 or (x – a)2 + b2 = 0.
    Step 5: Take the constant term to the other side of the equation.
    Step 6: Take the square root on both the sides of the obtained equation to get the roots of the given quadratic
    equation.

  3. Quadratic formula
    The roots of a quadratic equation  ax2 + bx + c = 0 (a ≠ 0) can be calculated by using the quadratic
    formula:
    begin mathsize 11px style fraction numerator negative straight b plus square root of straight b squared minus 4 ac end root over denominator 2 straight a end fraction and space fraction numerator negative straight b minus square root of straight b squared minus 4 ac end root over denominator 2 straight a end fraction comma where space straight b squared minus 4 ac greater or equal than space 0 end style
    If b2 – 4ac < 0, then equation does not have real roots.
  • Discriminant of a quadratic equation
    For the quadratic equation ax2 + bx + c = 0, a ¹ 0, the expression b2 – 4ac is known as discriminant.
  • Nature of Roots
    Let f(x) = ax2 + bx + c = 0 be the quadratic equation, the discriminant D = b2 – 4ac.



  • Relation between roots and coefficients:
    Let a, b  be the roots of the quadratic equation ax2 + bx + c = 0  then
  1. begin mathsize 11px style text Sum of the roots =α+β = end text straight b over straight alpha end style
  2. begin mathsize 11px style Product space of space the space roots  =  straight alpha. straight beta equals straight c over straight alpha end style

Note: Quadratic equation can be rewritten as.x2-(α+β) x+ α.β =0

  • Equations reducible to Quadratic Equations
    There are many equations which are not in the quadratic form but can be reduced to the quadratic form by simplifications.
    Type I: ax2n + bxn + c = 0
    Put xn = y
    So, the equation reduces to  ay2 + by +c = 0
    Now solve for y and hence for x.
    Type II:  begin mathsize 11px style text az+ end text straight b over straight z equals straight c end style where a, b, c are constants
    Make it  az2 – cz + b = 0
    Now, solve it for z.

    Type III: (x+a) (x=b) (x+c) (x+d)+ k = 0,where the sum of two of the quantities   is equal to the sum of the other tw)o.
    Example:
    (x+1)(x+2)(x+3)(x+4) + 1= 0
    As sum of 1 and 4 is equal to sum of 2 and 3
    ⟹ [(x+1)(x+4)][(x+2)(x+3)+1 =0
    ⟹ (x2 + 5x +4 )(x2+5x+6)+1=0
    Take  x2+5x =y
    ⟹ (y+4)(y+6)+1=0
    ⟹ y2+10y+24+1=0
    ⟹ y2+10y +25 =0
    ⟹ (y+5)2 =0
    ⟹ y=-5
    ⟹ x2 +5x+5=0

    begin mathsize 11px style text ⇒x= end text fraction numerator negative 5 plus-or-minus square root of 25 minus 20 end root over denominator 2 end fraction
rightwards double arrow straight x equals fraction numerator negative 5 plus-or-minus square root of 5 over denominator 2 end fraction end style
  • Formation of Equations with given roots
    Suppose the given roots are α and β
    Therefore x = α and x =β
    ⟹ (x- α) = 0 and (x- β ) =0
    The equation forms will be
    (x- α)(x- β)=0
    ⟹ x2 –( α+ β)x+ α β=0
    ⟹ x2-(sum of roots)x + Product of roots =0
  • Applications of quadratic equations
  • The applications of quadratic equation can be utilized in solving real life problems.
  • Following points can be helpful in solving word problems:
  • Every two digit number ‘xy’ where x is a ten’s place and y is a unit’s place can be expressed as. Xy= 10x +y.
  • Downstream: It means that the boat is running in the direction of the stream
    Upstream: It means that the boat is running in the opposite direction of the stream
    Thus, if
    Speed of boat in still water is x km/h
    And the speed of stream is y km/h
    Then the speed of boat downstream will be (x + y) km/h and in upstream it will be (x − y) km/h.
    If a person takes x days to finish a work, then his one day's work begin mathsize 11px style text = end text 1 over straight x end style
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