Fri February 29, 2008 By:

word problem??

Expert Reply
Fri February 29, 2008

an optically active compound 'A' C4H9Br, on reduction gives optically inactive compound 'B'. 'A' on reaction with KOH(alc.) gives 'C' which on reaction with HBr gives 'A'  back. identify A,B and C and write the chemical reactions involved?

A  is CH3CH2CHBrCH3 will be optically active with chiral carbon atom.


C isCH3CH=CHCH3 elimination will be by satzeffs rule.


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