Question
Sun December 25, 2011 By:

when a momentum of a body increases by 100 percent then its kinetic energy increases by ___________.

Expert Reply
Sun December 25, 2011
p'=100% x p + p 
  =2p
K'=(p')2/2m
  =4p2/2m=4K = 3K + K = 300% K + K
KE becomes four times. It means that the kinetic energy increases by 300%.
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