Wed June 06, 2012 By:

Wavelength of first line in Balmer series in hydrogen spectrum is 6563Aongston.Calculate the wavelength of the second line in this series.

Expert Reply
Fri June 08, 2012
lamda ?=6563
1/? =R[1/22-1/32]   R is rydberg constant=1.097x107
second line:
1/? =R[1/22-1/42]
solve then u get , wave length=3693A
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