a boy is running on a straight road. he runs 500m towards north in 2hrs 10 min and then turns back and runs 200m/sin 1hr.calculate
1)his average speed and magnitude of avg velocity during first 2 hrs 10 min
2)average speed and velocity
During first 2hr 10 min :
speed = distance / time
here distance = 500m
time = 2hr 10 min = 130 min = 780 sec.
so , speed = 500m / 780sec
Also average velocity = 0.64 m/s.
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