Question
Mon September 28, 2009 By: Khushal Gupta

Trigonometry.

Expert Reply
Mon September 28, 2009

xcos θ/a +ysin θ/b = 1

xsin θ/a - ycos θ/b = 1

Squaring and adding,

x2cos2 θ/a2 +2(xcos θ/a)(ysin θ/b) + y2sin2 θ/b2 + x2sin2 θ/a2 - 2(xsin θ/a)(ycos θ/b) + y2cos2 θ/b2 = 2

x2(cos2 θ + sin2 θ)/a2 + y2(sin2 θ +cos2 θ)/b2 = 2

x2/a2 + y2/b2 = 2

Regards,

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