Question
Wed September 30, 2009 By:

Trigonometry

Expert Reply
Wed September 30, 2009

[(sinA + cosA)/(sinA - cosA)] + [(sinA - cosA)/(sinA + cosA)]

= [(sinA + cosA)2 + (sinA - cosA)2]/(sin2A - cos2A)

= 2/(sin2A - cos2A) .................Using (a ± b)2 = a2 ± 2ab + b2

Dividing numerator and denominator by cos2A

= 2sec2A/(tan2A - 1)

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