Question
Fri February 20, 2009 By:

to prove

Expert Reply
Fri February 20, 2009

(p x q). [(q x r) x (r x p)]

= (p x q). [ r ( (qxr).p ) - p ( (qxr).r ) ]

here (qxr) . r = 0  then

=(p x q). [ r ( (qxr).p ) ]

= (pxq).r [ q r p]    ( [q r p ] =  [p q r ] )

= [p q r ] [p q r ]

= [p q r ]2

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