Sun February 17, 2013 By: Sahil

The shadow of a building, when the angle of elevation of the sun is 45degrees is found to be 10 cm longer than when it was 60degrees . Find the height of the Building.

Expert Reply
Sun February 17, 2013
Let AB be the building. Let AB = h and BC = x
In right triangle ABD,
tan 45 = AB/BD
1 = h/10+x
h = 10+x
In right triangle ABC,
tan 60 = AB/BC
?3 = h/x
From the above two equations, eliminate x and find h (height of the building).
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