Thu March 27, 2014 By: Sanskrati Gawande

the ionization constant of acetic is   1.74*10-5  calculate the degree of dissociation of acetic acid in 0.05m solution calculate the concetration of acetate ions in solution and ph of the solution?

Expert Reply
Thu March 27, 2014

Method 1

Since Ka >> Kw, :

Method 2

Degree of dissociation,

c = 0.05 M

Ka = 1.74 × 10–5


Thus, concentration of CH3COO = c.α 


Hence, the concentration of acetate ion in the solution is 0.00093 M and its Ph is 3.03.

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