sum of the areas of two square is 530m2. if the difference of their perimeter is 24m,find the sides of the two squares.
let the sides of squares are a and b respectively so we have a2 + b2 = 530 and 4a - 4b = 24 ===> a-b = 6
we also have (a-b)2 = a2 + b2 - 2ab putting above values we get ab = 247
we also have (a+b) 2 = (a-b)2 + 4ab putting above value we get a+b = 32
so a= 19 and b = 13