Question
Wed January 04, 2012 By: Mahesh Joshi

Solution

Expert Reply
Thu January 05, 2012

Carbonate (CO32- ) is the conjugate base of the weak acid HCO3-  so when CO32- is placed in water, it reacts to some extent with the water and takes away a proton from it and produces HCO3- and OH-. Now we know that OH- is a strong base so the solution of sodium carbonate becomes alkaline.

The reaction is as follows:

CO32- + H2O ----> HCO3- + OH-

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