Question
Tue April 14, 2015 By: Sriradha Gupta

Sir, could you please solve this one?
Sir, could you please solve this one, Question no 89590, Mathematics

Expert Reply
Vimala Ramamurthy
Wed April 15, 2015
G i v e n space t h a t comma space x over 7 equals y over 3 equals fraction numerator 2 x minus 3 y over denominator 9 minus a end fraction. L e t space x over 7 equals y over 3 equals m rightwards double arrow space x equals 7 m space a n d space y equals 3 m rightwards double arrow 2 x minus 3 y equals 2 open parentheses 7 m close parentheses minus 3 open parentheses 3 m close parentheses equals 14 m minus 9 m T h u s comma space fraction numerator 2 x minus 3 y over denominator 9 minus a end fraction equals fraction numerator 14 m minus 9 m over denominator 9 minus a end fraction... left parenthesis 1 right parenthesis B u t space sin c e space x over 7 equals y over 3 equals m comma space w e space h a v e comma space fraction numerator 2 x minus 3 y over denominator 9 minus a end fraction equals m F r o m space e q u a t i o n space left parenthesis 1 right parenthesis comma space w e space h a v e comma fraction numerator 14 m minus 9 m over denominator 9 minus a end fraction equals m rightwards double arrow fraction numerator 6 m over denominator 9 minus a end fraction equals m rightwards double arrow fraction numerator 6 over denominator 9 minus a end fraction equals 1 rightwards double arrow 6 equals 9 minus a rightwards double arrow a equals 9 minus 6 rightwards double arrow a equals 3
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