An electric lamp of 100 Ohms, a toaster of resistance 50 Ohms, and a water heater of resistance 500 Ohms are connected in parallel to a 220 V source. What is the resistance of an electric iron connected to the same source that takes as much current as
In order to have same current as the other appliances in combination have, the resistance of the iron should be equal to the resultant resistance of the appliances connected in parallel.
1/ Rtotal =(1/100) + (1/50) + (1/500)
1/ Rtotal =(5 + 10 + 1) / 500
Rtotal = (500 / 16) ohm
Current i = V / Rtotal = 220 x 16 / 500 = 7.04 A