Question
Wed February 18, 2009 By: Namrata Priyadarshini

question

Expert Reply
Thu February 19, 2009

Resistance when 10 bulbs are in parallel,R||=R/10

Resistance when 10 bulbs are in series,Rseries=10R

Voltage acros each bulb in first case is V while in second case is V/10. So first circuit has highest voltage across each bulb. But current in second circuit across each bulb is 10 times that flowing across each blb in first case. So 

power dissipated is more in second case per bulb. Thus bulbs brighten more in second case.

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