Question
Wed January 11, 2012 By:

Question:

Expert Reply
Thu January 12, 2012
Here, W = 2, R = 3, G = 5, B = 4
Since two balls are drawn with out replacement.
So, Prob. of getting both balls of different colours = 1 - Prob. that both are of same colour
= 1 - [P(both red) + P(both red) + P(both green) + P(both black)]
= 1- [2C2/14C2 + 3C2/14C2 + 5C2/14C2 + 4C2/14C2]
= 1- [1/91 + 3/91 + 10/91 + 6/91]
= 1- [20/91]
=71/91
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