Question
Tue September 01, 2009 By:

q34

Expert Reply
Wed September 02, 2009

log (4y-3)=log(2y+1) - log3

log(4y-3)=log(2y+1)/3

taking antilogs,

4y-3=(2y+1)/3

12y - 9 = 2y + 1

10y = 10

y = 1

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