Question
Wed February 18, 2009 By: Namrata Priyadarshini

problem sum

Expert Reply
Thu February 19, 2009

Let the resistance of electric iron connected may be R.

We have R=R1||R2||R3

1/R= 1/100+1/50+1/500= (5+10+1)/500

R=31.25 ohms

Current through it,I=V/R=220/31.25=7.04 A

Home Work Help