Question
Fri April 02, 2010 By:

Probability

Expert Reply
Sat April 03, 2010

P(AUB)= 0.6

P(AB) = 0.2

P(AUB)=P(A)+P(B)-P(AB)

0.8 =P(A)+P(B)

 P(A¯)+P( B¯) = 2-P(A)+P(B)

 P(A¯)+P( B¯)=2-0.8 =1.2

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