Question
Sat March 02, 2013 By:

Plz answer fast as my exam is tomorrow .

Expert Reply
Mon March 04, 2013
when going up: max ht it reaches:h
v2-u2=2gh
2x10xh=20x20
h=20 m
v=u-gt
t=2s....to reach the highest height.
while cominbg down: it has to cover=105+20=125m
u=o
so:  s=ut+1/2  at^2
125=5t^2
t=5sec
so total time=5+2=7 s
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