Question
Mon September 07, 2009 By: Jayant Kaushik

plese solve it as soon as possible

Expert Reply
Mon September 07, 2009

f(x) = 6x3 - 11x2 + kx - 20

f(4/3) = 0.

6(4/3)3 - 11(4/3)2 + k(4/3) - 20 = 0

6(64/27) - 11(16/9) + k(4/3) - 20 = 0

k(4/3) = 20(27)/27 + 11(3)(16/27) - 6(64/27)

k(4/3) = [20(27) + 11(3)(16) - 6(64)]/27

k = 19.

Regards,

Team,

TopperLearning.

 

 

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