Question
Sat October 20, 2012 By:
 

please give the proof of relation= h'/h= -v/u

Expert Reply
Sun October 21, 2012
from triangles ABP and A'B'P
AB/A'B' = BP/B'P
(-h)/h'= (-u)/(-v)              using sign conventions
hence
h/h' = - u/v
Sat September 23, 2017

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