Question
Thu November 08, 2012 By: Tabish

indefinite integration

Expert Reply
Thu November 08, 2012
For the integration of v/(4+3v) dv
we first need to express the numerator in terms of denominator so as
to simplify the expression, so that it can be integrated using simpler
formulas.
Now, 
v/4+3v = 3v/3(4+3v)
 = 3v+4-4/3(4+3v)
 = 1/3  - 4/3(4+3v)
 
So the integral becomes,
?1/3 dv - 4/3?dv/(4+3v)
= v/3  - 4/9 ln(4+3v)
 
This is the answer
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