Wed June 13, 2012 By: Soha

if x^cosy+y^cosx=1'then find the value of dy/dx

Expert Reply
Wed June 20, 2012

xcosy = ycosx

Taking log on both the sides,

cos y log x= cos x logy

cos y (1/x) + log x (-sin y) (dy/dx) = cos x (1/y)(dy/dx) + logy (-sinx)

dy/dx ((-siny log x) – (cosx/y))= -logy (sinx)-(cosy/x)

dy/dx= (logy (sinx)+(cosy/x))/ ((siny log x) +(cosx/y))

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