Question
Sat December 01, 2012 By:

# IF ? AND ? ARE THE ROOTS OF THE QUADRATIC EQUATION ax (WHERE X IS RAISED TO THE POWER 2)+bx+c=0 ,THEN FIND THE QUADRATIC EQUATION WHOSE ROOTS ARE 1)2? , 2? 2)?(where alpha is raised to the power 2) ,?(where beta is raised to the power 2) 3)1+?/1-? , 1+?/1-? 4)?/? , ?/?

Sun December 02, 2012
from sum of roots and product of roots we can say
?+?=-b/a
??=c/a
i) for the new equation
Sum of roots=2?+2?=2(?+?)=-2b/a
product of roots=2?*2?=4??=4c/a
therfor new equation
X^2+2b/a X+4c/a=0
or, aX^2-2bX+4c=0

Similarly in rest of the parts find sum and product of roots of the new equation and the equation can be written as

X^2-(sum of rrots)*X+(product of roots)=0
Related Questions
Wed September 13, 2017

# TO TOPPER LEARNING TEAM - Is there any expert in topper learning team who can reply my queries with proper logic else regret the same. Plz also arrange to remove wrong reply of experts against my questions raised. THIS REFERS TO SOLUTION PROVIDED BY YOU OF ATTACHED QUESTION. YOUR EXPERT SNEHA HAS MENTIONED THAT (X+1)(X^2+X+1)= X^3+2X^2+2X+1=0 HAS ROOT -1 AND IT IS ALWAYS -d/a. MY QUESTION IS WHY IT IS NOT (a-b)/a. PLEASE REPLY WITH PROPER LOGIC.

Mon September 11, 2017