Question
Sun September 29, 2013 By:
 

if a,b,c are all non-zero and a+b+c=0,prove that a2/bc+b2/ca+c2/ab=3

Expert Reply
Sun September 29, 2013
We know that if a+b+c =0 , then a3 + b3 + c3 = 3abc
 
Now, we have:
LHS = a2/bc+b2/ca+c2/ab
= a3+b3+c3/abc
= 3abc/abc
= 3 = RHS
Hence, proved
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