Thu December 22, 2011 By: Sai-netra Ramesh

how have the formulae come for moment of inertia of these rigid bodies??

Expert Reply
Fri December 23, 2011
for example, take  a disc of mass M and radius R.
take a small circular portiopn on the disc of width dx  at a distance  x from the centre.
mass per unit area of the disc is constant through out.
the mass of the is part=(M/pi R2)area of the  small part
=(M/pi R2)2 pi x dx
moment of inertia of this part=((M/pi R2)2 pi x dx)x2
moment of inertia of the disc=?(M/pi R2)2 pi x3 dx
                                        put limit from 0 to R
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