Question
Fri February 20, 2009 By:

How do I solve the following??

Expert Reply
Fri February 20, 2009

Let it be placed at a distance y from 4Q and x-y from 2Q.

or equilibrium we have:

k4Qq/(y2 )=k2Qq/(x-y)2

Hence, 2(x-y)2 =y2

y2 -4xy+2x2 =0

Hence ,y= x(4-2(2)0.5 )/2

 

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