Question
Thu February 19, 2009 By:

haarshit ..........triangles.........................???///

Expert Reply
Fri February 20, 2009

in triangle ACD ,tanA =CD/AD...(1)
in triangle BCD ,tanB =CD/BD...(2)
Dividing above two eqn,we get:
tanB/tanA=AD/BD=(AC/BC)/(BC/AC)=(AC/BC)2



Home Work Help