a bag contains 3 white and 2 red balls and another bag contains 2 white and 4 red balls. a ball is taken from the first bag and without seeing its colour is put in the second bag. a ball is taken from the latter. find the probability tha
find the probability
There are two possibilities : either the ball drawn from the first bag is white or it is red.
So the experiment has to take into account both these possibilities.
Total number of balls in the first bag =5
Total number of balls in the second bag =6
If the ball drawn is white and it's transferred to the second bag , then the number of balls in the second bag increses by 1 i.e it becomes 7 , but the number of red balls in the second bag remains unchanged.So the probability of drawing a white ball from the first bag , transferring it to the second bag and then drawing a red ball from the second bag =(3/5)*(4/7)=12/35
If the first ball drawn is red, then the number of balls in the second bag =7 and number of red balls in the second bag=5
So the probability =(2/5)*(5/7)=10/35
A circle is of radius 8 units. Then the probability that a randomly chosen point inside the circle is
closer to the centre than the circumference, is