Question
Tue March 20, 2012 By: Kumar Krishna

find the differentiation

Expert Reply
Wed March 21, 2012
Put costheta = (1- tan2theta/2 )/(1 + tan2theta/2)
So on solving we get sin-1 [ {(a+b) - (b-a)tan2theta/2}/{(a+b) + (b-a)tan2theta/2}]
which is pie/2 - 2tan-1[root(b-a)tantheta/2]
so we can easily find dy/dx = -root(b-a).sec2(theta/2) / ( 1 + (b-a)tan2theta/2 )
Home Work Help