Mon February 16, 2009 By:


Expert Reply
Tue February 17, 2009

Charge Q will be same on both the capacitors that are in series.

For capacitor A

Q = C1(40V )

For capacitor B

Q = C2(60V)

So C1/C2 = 3/2

C1 = 3x and C2 = 2x

On connecting 6 microfarad with B the potential drop is equal to that across A, so the capacitance of this combination is equal to the capacitance of A.

Now you can write an equation in variable x and solve it to find C1 and C2.

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