Question
Fri February 01, 2013 By: Manoj
Expert Reply
Sat February 02, 2013
consider x=a^2 tan?
so sin^-1{tan?/sec?}
       sin^-1{sin?}
=?
=tan^-1(x/a^2)
diff. w.r. to x
=1/(1+x^2/a^4)   *1/a^2
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